如何打印标志 + Python 中正数的数字

Question

有没有更好的方法在正数上打印数字的+号？

integer1 = 10
integer2 = 5
sign = ''
total = integer1-integer2
if total > 0: sign = '+'
print 'Total:'+sign+str(total)

0 应该返回 0，不带 +。

Answer 1

使用新字符串格式，

>>> '{0:+} number'.format(1)
'+1 number'
>>> '{0:+} number'.format(-1)
'-1 number'
>>> '{0:+} number'.format(-37)
'-37 number'
>>> '{0:+} number'.format(37)
'+37 number'
# As the questions ask for it, little trick for not printing it on 0
>>> number = 1
>>> '{0:{1}} number'.format(number, '+' if number else '')
'+1 number'
>>> number = 0
>>> '{0:{1}} number'.format(number, '+' if number else '')
'0 number'

建议 而不是%操作员

Answer 2

>>> print "%+d" % (-1)
-1
>>>
>>> print "%+d" % (1)
+1
>>> print "%+d" % (0)
+0
>>>

这是文档。

**更新** 如果出于某种原因您无法使用 % 运算符，则不需要函数：

>>> total = -10; print "Total:" + ["", "+"][total > 0] + str(total)
Total:-10
>>> total = 0; print "Total:" + ["", "+"][total > 0] + str(total)
Total:0
>>> total = 10; print "Total:" + ["", "+"][total > 0] + str(total)
Total:+10
>>>

Answer 3

从 python 3.6 开始：

>>> integer1 = 10
>>> integer2 = 5
>>> total = integer1-integer2
>>> print(f'Total: {total:+}')
Total: +5

或：

for i in range(-1,2):
    print (f' {i} becomes {i:+}')

输出：

 -1 becomes -1
 0 becomes +0
 1 becomes +1