通过WMI获取启动列表

Question

如何获取完整的 .exe 路径

让我们假设使用以下字符串 strt["Command"].ToString(); 我得到这个输出

C:\Program Files\模拟 Devices\SoundMAX\soundmax.exe /tray

但如何获取

C:\Program Files\模拟 设备\SoundMAX\soundmax.exe

ManagementClass mangnmt = new ManagementClass("Win32_StartupCommand");
ManagementObjectCollection mcol = mangnmt.GetInstances();
foreach (ManagementObject strt in mcol)
{
    string[] lv = new String[4];
    lv[0] = strt["Caption"].ToString();
    lv[1] = strt["Location"].ToString();
    lv[2] = strt["Command"].ToString();
    lv[3] = strt["Description"].ToString();
    listView1.Items.Add(new ListViewItem(lv, 0));
}

Answer 1

   FileInfo fi = new FileInfo(@"C:\Program Files\Analog Devices\SoundMAX\soundmax.exe /tray");
   Console.WriteLine(fi.DirectoryName);