在 Django 中通过 save() 使 Memcached 键失效

Question

我在 Django 中有一个视图，它使用 memcached 为依赖于相对静态数据集的流量较高的视图缓存数据。关键词是相对的：当数据库中的特定 URL 数据发生更改时，我需要使 memcached 密钥无效。为了尽可能清楚，这是视图的要点（人是一个模型，缓存是 django.core.cache.cache）：

def person_detail(request, slug): 
    if request.is_ajax():
        cache_key = "%s_ABOUT_%s" % settings.SITE_PREFIX, slug

        # Check the cache to see if we've already got this result made.
        json_dict = cache.get(cache_key)

        # Was it a cache hit?
        if json_dict is None:
            # That's a negative Ghost Rider
            person = get_object_or_404(Person, display = True, slug = slug)

            json_dict = {
                'name' : person.name,
                'bio' : person.bio_html,
                'image' : person.image.extra_thumbnails['large'].absolute_url,
            }

            cache.set(cache_key)

        # json_dict will now exist, whether it's from the cache or not
        response = HttpResponse()
        response['Content-Type'] = 'text/javascript'
        response.write(simpljson.dumps(json_dict)) # Make sure it's all properly formatted for JS by using simplejson
        return response
    else:
        # This is where the fully templated response is generated

我想要做的是以“未格式化”的形式获取该 cache_key 变量，但我不确定如何做到这一点——如果可以的话。

以防万一已经有一些东西可以做到这一点，这就是我想要用它做的事情（这是来自 Person 模型的假设保存方法）

def save(self):    
    # If this is an update, the key will be cached, otherwise it won't, let's see if we can't find me
    try:
        old_self = Person.objects.get(pk=self.id)
        cache_key = # Voodoo magic to get that variable
        old_key = cache_key.format(settings.SITE_PREFIX, old_self.slug) # Generate the key currently cached
        cache.delete(old_key) # Hit it with both barrels of rock salt

    # Turns out this  doesn't already exist, let's make that first request even faster by making this cache right now
    except DoesNotExist:
        # I haven't gotten to this yet.

    super(Person, self).save()

我正在考虑为这种东西创建一个视图类，并在其中包含像 < code>remove_cache 或 generate_cache 因为我经常做这种事情。那是一个更好的主意吗？如果是这样，如果 URLconf 中的视图在一个类中，我将如何调用它们？

Answer 1

URLConf 应该指向任何可调用的。没有严格要求使其能够准确运行。您可以使用缓存方法实现基类，然后扩展它：

class RealView(BaseViewWithCacheMethods):
    def __call__(self, request):
        if request.is_ajax():
            return self.ajax_view()
        return self.html_view()

URLConf 定义将类似于：

from django.conf.urls.defaults import *
from views import RealView

urlpattrens = patterns('',
    (r'^
, RealView()),
)