转换字符串列表 [ '3', '1', '2' ] 到已排序整数列表 [1, 2, 3]

Question

我有一个字符串表示形式的整数列表，类似于以下内容：

L1 = ['11', '10', '13', '12', 
      '15', '14',  '1',  '3', 
       '2',  '5',  '4',  '7', 
       '6', '9', '8']

我需要将其设为一个整数列表，例如：

L2 = [11, 10, 13, 12, 15, 14, 1, 3, 2, 5, 4, 7, 6, 9, 8]

最后我将按如下方式对其进行排序：

L3 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15] # by L2.sort()

请让我知道从 L1 获取的最佳方式是什么 到 L3？

Answer 1

您可以像这样一步完成：

L3 = sorted(map(int, L1))

更详细地说，步骤如下：

>>> L1 = ['11', '10', '13', '12', '15', '14', '1', '3', '2', '5', '4', '7', '6', '9', '8']
>>> L1
['11', '10', '13', '12', '15', '14', '1', '3', '2', '5', '4', '7', '6', '9', '8']
>>> map(int, L1)
[11, 10, 13, 12, 15, 14, 1, 3, 2, 5, 4, 7, 6, 9, 8]
>>> sorted(_)
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
>>>

Answer 2

>>> L1 = ['11', '10', '13', '12', '15', '14', '1', '3', '2', '5', '4', '7', '6', '9', '8'] 
>>> L1 = [int(x) for x in L1]
>>> L1
[11, 10, 13, 12, 15, 14, 1, 3, 2, 5, 4, 7, 6, 9, 8]
>>> L1.sort()
>>> L1
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
>>> L3 = L1

Answer 3

L3 = sorted(int(x) for x in L1)