Java GAE 数据存储上的子查询

发布于 2024-08-30 02:38:18 字数 1426 浏览 3 评论 0原文

我正在尝试创建一个具有用户之间连接的用户数据库(朋友列表)。 有 2 个主表:UserEntity(主字段 id)和 FriendEntity,其字段为: - initiatorId - 发起友谊的用户的id -friendId - 已被邀请的用户的id。

现在我正在尝试获取某个特定用户的所有朋友,并在此处使用 JDO 中的子查询时遇到了一些问题。

从逻辑上讲,查询应该是这样的: SQL: SELECT * FROM UserEntity WHERE EXISTS (SELECT * FORM FriendEntity WHERE (initiatorId == UserEntity.id &&friendId == userId) || (friendId == UserEntity.id && initiatorId == userId))

或SELECT * FROM UserEntity WHERE userId IN (SELECT * FROM FriendEntity WHERE initiatorId == UserEntity.id) OR userId IN (SELECT * FROM FriendEntity WHEREfriendId == UserEntity.id)

因此,为了复制 JDOQL 中的最后一个查询,我尝试执行以下操作以下:

Query friendQuery = pm.newQuery(FriendEntity.class);
friendQuery.setFilter("initiatorId == uidParam");
friendQuery.setResult("friendId");

Query initiatorQuery = pm.newQuery(FriendEntity.class);
initiatorQuery.setFilter("friendId == uidParam");
initiatorQuery.setResult("initiatorId");


Query query = pm.newQuery(UserEntity.class);
query.setFilter("initiatorQuery.contains(id) || friendQuery.contains(id)");
query.addSubquery(initiatorQuery, "List initiatorQuery", null, "String uidParam");
query.addSubquery(friendQuery, "List friendQuery", null, "String uidParam");
query.declareParameters("String uidParam");

List<UserEntity> friends = (List<UserEntity>) query.execute(userId);

结果我收到以下错误: 解析表达式时不支持的方法。

有人可以帮忙解决这个问题吗?

I am trying to create a database of users with connection between users (friends list).
There are 2 main tables: UserEntity (main field id) and FriendEntity with fields:
- initiatorId - id of user who initiated the friendship
- friendId - id of user who has been invited.

Now I am trying to fetch all friends of one particular user and encountered some problems with using subqueries in JDO here.

Logically the query should be something like this:
SQL: SELECT * FROM UserEntity WHERE EXISTS (SELECT * FORM FriendEntity WHERE (initiatorId == UserEntity.id && friendId == userId) || (friendId == UserEntity.id && initiatorId == userId))

or SELECT * FROM UserEntity WHERE userId IN (SELECT * FROM FriendEntity WHERE initiatorId == UserEntity.id) OR userId IN (SELECT * FROM FriendEntity WHERE friendId == UserEntity.id)

So to replicate the last query in JDOQL, I tried to do the following:

Query friendQuery = pm.newQuery(FriendEntity.class);
friendQuery.setFilter("initiatorId == uidParam");
friendQuery.setResult("friendId");

Query initiatorQuery = pm.newQuery(FriendEntity.class);
initiatorQuery.setFilter("friendId == uidParam");
initiatorQuery.setResult("initiatorId");


Query query = pm.newQuery(UserEntity.class);
query.setFilter("initiatorQuery.contains(id) || friendQuery.contains(id)");
query.addSubquery(initiatorQuery, "List initiatorQuery", null, "String uidParam");
query.addSubquery(friendQuery, "List friendQuery", null, "String uidParam");
query.declareParameters("String uidParam");

List<UserEntity> friends = (List<UserEntity>) query.execute(userId);

In result I get the following error:
Unsupported method while parsing expression.

Could anyone help with this query please?

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(1

离旧人 2024-09-06 02:38:18

您正在尝试进行联接 - 您无法跨实体进行联接。

这是一个在存在拥有关系的情况下执行简单联接的示例
http://gae-java- persistence.blogspot.com/2010/03/executing-simple-joins-across-owned.html

另请查看该网站,它有很多关于如何使持久性工作发挥作用的非常好的信息。以及一些连接的解决方法。

您可以在实体之间设置关系,请参阅 GAE 文档。

You are trying to do a join - You cannot do joins across Entities.

Here is an example of doing a simple join if there is an owned relationship
http://gae-java-persistence.blogspot.com/2010/03/executing-simple-joins-across-owned.html

Also look at that web site it has a lot of really good information on getting the persistence stuff to work. as well as a couple of work-arounds for joins.

You can set up relationships among Entities, for that see GAE docs.

~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文