多属性 xml 过滤器 as3 e4x

发布于 2024-08-30 02:05:53 字数 786 浏览 9 评论 0原文

我正在尝试提出最好的 xml 模式来支持标签过滤。然后是根据任意数量的标签过滤 xml 的方法。所以这里是 xml：

var videoXML:XML=
<?xml version="1.0" encoding="UTF-8"?>
    <videos>
        <video> <tags label="dogs,brown,lawns" /> </video>
        <video> <tags label="dogs,cats" /> </video>
        <video> <tags label="cats,lawns" /> </video>
    </videos>

我现在过滤的方式是：

var filteredList:XMLList = videoXML..video.tags.(@label.indexOf("lawns") != -1 && @label.indexOf("dogs") != -1);

它只会返回带有“草坪”和“狗”标签的视频，这一切都很好。

但我想要一种方法，可以传入任意数量的标签并获取该过滤器的结果。

类似于：

function getFilteredByTags(...tags):XMLList{

}

关于如何实现这一点有什么想法吗？

谢谢！

原文

I am trying to come up with the best xml schema to support tag filtering. And then a method to filter the xml on an arbritary amount of tags. So here is the xml:

var videoXML:XML=
<?xml version="1.0" encoding="UTF-8"?>
    <videos>
        <video> <tags label="dogs,brown,lawns" /> </video>
        <video> <tags label="dogs,cats" /> </video>
        <video> <tags label="cats,lawns" /> </video>
    </videos>

And the way I am filtering now is:

var filteredList:XMLList = videoXML..video.tags.(@label.indexOf("lawns") != -1 && @label.indexOf("dogs") != -1);

which would return only videos that had the tag "lawns" and "dogs", which is all good and fine.

But I want a method that I can pass in as many tags as I want and get the results of that filter.

Something like:

function getFilteredByTags(...tags):XMLList{

}

Any ideas on how to accomplish this?

Thanks!

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金橙橙 2024-09-06 02:05:53

我想不出更好的方法，但您的函数可以计算有多少个标签，然后对该计数运行 switch 语句并对标签数量执行正确的 e4x。

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滿滿的愛 2024-09-06 02:05:53

未经测试，但应该可以工作。™

将您的 XML 更改为：

var videoXML:XML=
<?xml version="1.0" encoding="UTF-8"?>
<videos>
    <video>
        <tag label="dogs" />
        <tag label="brown" />
        <tag label="lawns" />
    </video>
    <video>
        <tag label="dogs" />
        <tag label="cats" />
    </video>
    <video>
        <tag label="cats" />
        <tag label="lawns" />
    </video>
</videos>

返回具有多个标签的视频的函数：

function getFilteredByTags(...tags):XMLList
{
    // Start with a list of all videos
    var foundVideos:XMLList = videoXML.video;

    for each (tag in tags)
    {
        // Filter foundVideos down to those videos that match tag
        foundVideos = foundVideos.(tag.@label == tag);
    }

    return foundVideos;
}

Untested, but Should Work.™

Change your XML to:

var videoXML:XML=
<?xml version="1.0" encoding="UTF-8"?>
<videos>
    <video>
        <tag label="dogs" />
        <tag label="brown" />
        <tag label="lawns" />
    </video>
    <video>
        <tag label="dogs" />
        <tag label="cats" />
    </video>
    <video>
        <tag label="cats" />
        <tag label="lawns" />
    </video>
</videos>

Function to return videos with multiple tags:

function getFilteredByTags(...tags):XMLList
{
    // Start with a list of all videos
    var foundVideos:XMLList = videoXML.video;

    for each (tag in tags)
    {
        // Filter foundVideos down to those videos that match tag
        foundVideos = foundVideos.(tag.@label == tag);
    }

    return foundVideos;
}

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