使用 PowerShell 清理文件夹

Question

我想在脚本运行后通过从当前目录中删除某些文件夹和文件（如果存在）来清理某些目录。最初，我是这样构建脚本的：

if (Test-Path Folder1) {
  Remove-Item -r Folder1
}
if (Test-Path Folder2) {
  Remove-Item -r Folder2
}
if (Test-Path File1) {
  Remove-Item File1
}

现在我在本节中列出了相当多的项目，我想清理代码。我怎样才能这样做呢？

旁注：这些项目在脚本运行之前被清理，因为它们是上次运行留下的，以防我需要检查它们。

Answer 1

# if you want to avoid errors on missed paths
# (because even ignored errors are added to $Error)
# (or you want to -ErrorAction Stop if an item is not removed)
@(
    'Directory1'
    'Directory2'
    'File1'
) |
Where-Object { Test-Path $_ } |
ForEach-Object { Remove-Item $_ -Recurse -Force -ErrorAction Stop }

Answer 2

Folder1, Folder2, File1, Folder3 |
    ?{ test-path $_ } |
        %{
            if ($_.PSIsContainer) {
                rm -rec $_ #  For directories, do the delete recursively
            } else {
                rm $_ #  for files, just delete the item
            }
        }

或者，您可以为每种类型创建两个单独的块。

Folder1, Folder2, File1, Folder3 |
    ?{ test-path $_ } |
        ?{ $_.PSIsContainer } |
            rm -rec

Folder1, Folder2, File1, Folder3 |
    ?{ test-path $_ } |
        ?{ -not ($_.PSIsContainer) } |
            rm

Answer 3

一种可能性

function ql {$args}

ql Folder1 Folder2 Folder3 File3 |
    ForEach {
        if(Test-Path $_) {
            Remove-Item $_
        }
    }

Answer 4

# if you do not mind to have a few ignored errors
Remove-Item -Recurse -Force -ErrorAction 0 @(
    'Directory1'
    'Directory2'
    'File1'
)