从 XML 文件中删除标头的简单方法

Question

我需要从另一个程序生成的文件中删除非 xml 标签。

该文件是这样的：

Executing Command - Blah.exe ...
-----Command Output-----
HTTP/1.1 200 OK
Connection: close
Content-Type: text/xml

<?xml version="1.0"?>
<testResults>
  <finalCounts>
    <right>7</right>
    <wrong>4</wrong>
    <ignores>0</ignores>
    <exceptions>0</exceptions>
  </finalCounts>
</testResults>

Exit-Code: 15

How to remove the non-xml text easy in java?

Answer 1

// getContent() returns the complete text to strip.
//
String s = getContent();

// Find the start of the XML content using the <?xml prefix.
//
int xmlIndex = s.indexOf( "<?xml" );

// Strip the non-XML header.
//
s = s.substring( xmlIndex );

// Find the last closing angle-bracket; should indicate end of the XML.
//
xmlIndex = s.lastIndexOf( ">" );

// Strip everything after the closing angle-bracket.
//
s = s.substring( 0, xmlIndex );

Answer 2

这看起来像直接 HTTP 输出...所以只需扫描前两个连续换行符（可能在它们前面有回车符）就会得到要过滤掉的前缀的末尾。