如何将 NSString* 转换为 ANTLR3_UINT8 或 ANTLR3_UINT16

发布于 2024-08-29 18:27:09 字数 299 浏览 7 评论 0原文

有人可以告诉我将 NSString* 转换为 ANTLR3 字符串（在 C 中使用）的正确方法是什么？

编辑：这似乎有效

   char buf[255];   
   if ( YES == [myNSString getCString:buf maxLength:255 encoding:NSStringEncodingConversionAllowLossy] )
   {
      pANTLR3_UINT8 theExpression = (pANTLR3_UINT8*)buf;
      ...

原文

Could somebody tell me what is the proper way to convert a NSString* to an ANTLR3 string (used in C) ?

EDIT: this seems to work

   char buf[255];   
   if ( YES == [myNSString getCString:buf maxLength:255 encoding:NSStringEncodingConversionAllowLossy] )
   {
      pANTLR3_UINT8 theExpression = (pANTLR3_UINT8*)buf;
      ...

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深居我梦 2024-09-05 18:27:09

假设您想要完整的字符串而不丢失，您可以使用以下代码：

NSString *myString = ...;
NSUInteger len = [myString lengthOfBytesUsingEncoding:NSUTF8StringEncoding];
char *buf = malloc(len + 1);
if ([myString getCString:buf maxLength:(len + 1) encoding:NSUTF8StringEncoding]) {
    // pANTLR3_UINT8 is equivalent to ANTLR3_UINT8*
    pANTLR3_UINT8 theExpression = (pANTLR3_UINT8) buf;
}
free(buf);

当然，如果字符丢失不重要，您可以使用其他编码。

Assuming that you want the complete string without loss, you can use the following code:

NSString *myString = ...;
NSUInteger len = [myString lengthOfBytesUsingEncoding:NSUTF8StringEncoding];
char *buf = malloc(len + 1);
if ([myString getCString:buf maxLength:(len + 1) encoding:NSUTF8StringEncoding]) {
    // pANTLR3_UINT8 is equivalent to ANTLR3_UINT8*
    pANTLR3_UINT8 theExpression = (pANTLR3_UINT8) buf;
}
free(buf);

Of course you can use another encoding if character loss is not important.

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