写入 PIC 上的 EEPROM
这里有PIC单片机编程器吗?
我正在学习一些使用 pickit2 和它附带的 16F690 芯片的 PIC 微控制器编程。我目前正在尝试各种设施。如果我在 MPLAB 中设置 EEPROM vaklue,我可以在代码中成功读取 EEPROM 中的一个字节,但我似乎无法使用 PIC 本身修改该值。根本没有发生任何事情,我也不会读回修改后的值,我总是得到原始值,这对我来说意味着写入不起作用?
这是我该部分的代码,我错过了什么吗?我知道我做了很多不必要的银行切换,我添加了其中的大部分,以确保在错误的银行上不会出现问题。
; ------------------------------------------------------
; Now SET the EEPROM location ZERO to 0x08
; ------------------------------------------------------
BANKSEL EEADR
CLRF EEADR ; Set EE Address to zero
BANKSEL EEDAT
MOVLW 0x08 ; Store the value 0x08 in the EEPROM
MOVWF EEDAT
BANKSEL EECON1
BSF EECON1, WREN ; Enable writes to the EEPROM
BANKSEL EECON2
MOVLW 0x55 ; Do the thing we have to do so
MOVWF EECON2 ; that writes can work
MOVLW 0xAA
MOVWF EECON2
BANKSEL EECON1
BSF EECON1, WR ; And finally perform the write
WAIT
BTFSC EECON1, WR ; Wait for write to finish
GOTO WAIT
BANKSEL PORTC ; Just to make sure we are on the right bank
Are there any PIC microcontroller programmers here?
I'm learning some PIC microcontroller programming using a pickit2 and the 16F690 chip that came with it. I'm working through trying out the various facilities at the moment. I can sucessfully read a byte from the EEPROM in code if I set the EEPROM vaklue in MPLAB but I don't seem to be able to modify the value using the PIC itsself. Simply nothing happens and I don't read back the modified value, I always get the original which implies to me that the write isn't working?
This is my code for that section, am I missing something? I know I'm doing a lot of unnecessary bank switches, I added most of them to ensure that being on the wrong bank wasn't the issue.
; ------------------------------------------------------
; Now SET the EEPROM location ZERO to 0x08
; ------------------------------------------------------
BANKSEL EEADR
CLRF EEADR ; Set EE Address to zero
BANKSEL EEDAT
MOVLW 0x08 ; Store the value 0x08 in the EEPROM
MOVWF EEDAT
BANKSEL EECON1
BSF EECON1, WREN ; Enable writes to the EEPROM
BANKSEL EECON2
MOVLW 0x55 ; Do the thing we have to do so
MOVWF EECON2 ; that writes can work
MOVLW 0xAA
MOVWF EECON2
BANKSEL EECON1
BSF EECON1, WR ; And finally perform the write
WAIT
BTFSC EECON1, WR ; Wait for write to finish
GOTO WAIT
BANKSEL PORTC ; Just to make sure we are on the right bank
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在 16F690 数据表的第 122 页上,详细介绍了写入EEPROM:
我注意到您特别遗漏了这一行:
如果始终设置 EEPGD,那么您将尝试写入程序内存(也称为覆盖闪存程序内存),除非您已经离开,否则它应该总是失败不遗余力地专门启用它。
除此之外,据我从阅读您的代码来看,其他一切看起来都很好。您可以轮询
EECON1.WR
而不是设置中断。这比让设备进入睡眠状态会消耗更多的电量,但当然,您应该一次只担心一件事。On page 122 of the 16F690 datasheet, it details the proper way to write to EEPROM:
I noticed that you are specifically missing this line:
If
EEPGD
is always set, then you'll try to write to program memory (aka overwrite the flash program memory) which should always fail unless you've gone out of your way to specifically enable that.Aside from that, as far as I can tell from reading your code, everything else looks fine. It's okay that you're polling
EECON1.WR
instead of setting an interrupt. It will cost you more power than putting the device to sleep, but of course you should just worry about one thing at a time.如果您使用高科技编译器,写入 EEPROM 就很简单
#include
然后在 main 中,
EEPROM_WRITE(0, 0x00);
或者真的;
我实际上还没有足够的勇气在汇编中编写我的PIC。
If you use the high tech compiler, writing to EEPROM is as simple as
#include <pic.h>
and then in main,
EEPROM_WRITE(0, 0x00);
or really;
I actually haven't been brave enough to write my PIC in assembly.
xc8编译器的方式:
The way for the xc8 compiler: