将 HQL 解析为 AST 结构并将 AST 转换回 HQL

发布于 2024-08-29 12:06:21 字数 589 浏览 1 评论 0原文

我有一个 HQL 查询：

query = select item.itemNumber from items item where item.stock>0 and item.price<100.00

我喜欢解析这个查询并将其转换为树结构：

AST queryTree = parse(query);

而不是我喜欢迭代节点，更改一些值，然后将树转换回字符串表示形式：

Iterator<ASTNode> it = queryTree.nodeIterator();
while(it.hasNext())
{
  ASTNode node = it.next();
  System.out.println( node.text() + "->" + node.value() );
}
query = queryTree.toString();

如果解析会很好如果违反 HQL 语法，方法会抛出异常，但这不是必需的。有谁知道如何实现这一点？ hibernate 是否提供任何 API 方法来完成该任务？

谢谢，

原文

I have a HQL query:

query = select item.itemNumber from items item where item.stock>0 and item.price<100.00

i like to parse this query and convert it into a tree structure:

AST queryTree = parse(query);

than i like to iterate through the nodes, change some values, and convert the tree back to a string represenation:

Iterator<ASTNode> it = queryTree.nodeIterator();
while(it.hasNext())
{
  ASTNode node = it.next();
  System.out.println( node.text() + "->" + node.value() );
}
query = queryTree.toString();

it would be nice if the parse method would throw Exceptions in case the HQL grammer is violated, but its not necessary.
Has anyone an idea how this can be accomplished? Are there any API methods offered by hibernate to accomplish that task?

Thanks,

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