精灵与线的碰撞
如果我有一个精灵，我将如何检查两点之间的碰撞？例如，在我正在制作的游戏中，我想绘制我的精灵碰撞的多条线。我认为如果我有很多平台，这比其他碰撞系统更灵活。
If I have a sprite, how would I check collision between two points? For example, in a game I am making, I would like to draw multiple lines that my sprite collides against. I'm thinking that this is more flexible than other collision systems if I had a lot of platforms.
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一些简单的逻辑可以帮助减少浪费的计算，即如果精灵的顶部低于这两个点，则不会发生碰撞。类似于简单的边界框碰撞检查。
完成此操作后，我建议您为您的线制定一个“公式”，然后检查精灵的哪些角位于该线的上方或下方。如果它们不都位于同一侧，就会发生碰撞。
例如，如果您的行是
y=x/2+2，从 x=-20 开始，到 x=20 结束，并且您的方形精灵 3 宽/高位于 (3,-1)那么你就有了 spirte 的四个点 (3,-1)(3,2)(6,2)(6,-1)。您计算出这两个 x 位置处的线的 y 值，这将在 x=3 处给出 y=3.5，在 x=6 处给出 y=5，所有这些 y 值都大于立方体的 y 值，因此立方体位于该线下方。Some simple logic can help reduce wasted calculation, ie if the top of the sprite is lower then both of the points, you can't have a collision. Sort of a simple bounding box collision check.
Once you have done that, I would suggest that you get a 'formula' for your line, then check which of the corners of your sprite lay above or below that line. If they do not all lie on the same side, you have a collision.
for instance, if your line was of
y=x/2+2, starting at x=-20 ending at x=20 and you had square sprite 3 wide/high at (3,-1) then you have the four points of your spirte (3,-1)(3,2)(6,2)(6,-1). You work out the y value of the line at those two x positions, which give you y=3.5 at x=3 and y=5 at x=6 all of those y values are greater then the y values of the cube, thus the cube is below the line.