创建 2 个字符数组的所有单词变体

发布于 2024-08-29 08:49:24 字数 551 浏览 3 评论 0原文

我有 2 个字符串集合例如：

List<string> one = new List<string>;
one.Add("a");
one.Add("b");
one.Add("c");

List<string> two = new List<string>;
two.Add("x");
two.Add("y");
two.Add("z");

我想做的是创建一个可以由此创建的所有单词变体的列表。但我只想创建 4 个字符的单词！例如，我想要这样的词：“

axax (from one[1],two[1],one[1],two[1])
ayax (from one[1],two[2],one[1],two[1])
azax (from one[1],two[3],one[1],two[1])

最终得到

czcz (from one[3],two[3],one[3],two[3])

任何有关生成此内容的最快和最佳方式的建议”

原文

I have 2 collections of caracter string
ex:

List<string> one = new List<string>;
one.Add("a");
one.Add("b");
one.Add("c");

List<string> two = new List<string>;
two.Add("x");
two.Add("y");
two.Add("z");

What i would like to do is create a list of all the variations of words that can be created from this.
But i only want to create 4 character words!
so for example i would want words like

axax (from one[1],two[1],one[1],two[1])
ayax (from one[1],two[2],one[1],two[1])
azax (from one[1],two[3],one[1],two[1])

eventually getting to

czcz (from one[3],two[3],one[3],two[3])

Any suggestions on the fastest and best way to generate this

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我家小可爱 2024-09-05 08:49:24

我怀疑这个解决方案是否会赢得任何速度奖，但它应该相当快：

var one = new [] { "a", "b", "c" };
var two = new [] { "x", "y", "z" };

var ot = from o in one from t in two select o + t;
var r = from f in ot from s in ot select f + s;
var list = r.ToList();

I doubt this solution will win any speed awards, but it should be reasonably quick:

var one = new [] { "a", "b", "c" };
var two = new [] { "x", "y", "z" };

var ot = from o in one from t in two select o + t;
var r = from f in ot from s in ot select f + s;
var list = r.ToList();

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