使用 PHP 将文件夹重命名为子文件夹

发布于 2024-08-29 07:48:07 字数 204 浏览 2 评论 0原文

我正在尝试通过重命名来移动文件夹。 test1 和 test2 文件夹均已存在。

rename(
 "test1",
 "test2/xxx1/xxx2"
);

我得到的错误是：重命名（...）：没有这样的文件或目录

我认为这是因为目录“xxx1”不存在。我怎样才能移动 test1 目录？

原文

I'm trying to move a folder by renaming it. Both the test1 and test2 folders already exist.

rename(
 "test1",
 "test2/xxx1/xxx2"
);

The error I get is: rename(...): No such file or directory

I assume this is because the directory "xxx1" does not exist.
How can I move the test1 directory anyway?

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歌枕肩 2024-09-05 07:48:07

您可能需要创建它要进入的目录，例如

$toName = "test2/xxx1/xxx2";

if (!is_dir(dirname($toName))) {
    mkdir(dirname($toName), 0777, true);
}

rename("test1", $toName);

mkdir 的第三个参数() 是“递归”的，这意味着您可以通过一次调用创建嵌套目录。

You might need to create the directory it is going into, e.g.

$toName = "test2/xxx1/xxx2";

if (!is_dir(dirname($toName))) {
    mkdir(dirname($toName), 0777, true);
}

rename("test1", $toName);

The third parameter to mkdir() is 'recursive', which means you can create nested directories with one call.

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半世晨晓 2024-09-05 07:48:07

为什么不首先通过创建父目录来确保所有父目录都存在？ mkdir - 使用递归参数。

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迟到的我 2024-09-05 07:48:07

您的假设是正确的，这是因为您的示例中的“xxx1”不存在。

因此，在 rename("oldname", "/some/long/nested/path/test2/xxx1/newname") 之前，您必须创建目录树结构： /some/long/nested /path/test2/xxx1/ 但在rename 函数调用时newname 文件（或目录）不得存在。

为了概括该解决方案，请查看以下朴素函数：

function renameWithNestedMkdir($oldname , $newname)
{
     $targetDir = dirname($newname); // Returns a parent directory's path (operates naively on the input string, and is not aware of the actual filesystem)

    // here $targetDir is "/some/long/nested/path/test2/xxx1"
    if (!file_exists($targetDir)) {
        mkdir($targetDir, 0777, true); // third parameter "true" allows the creation of nested directories
    }

    return rename($oldname , $newname);
}

// example call
renameWithNestedMkdir("oldname", "/some/long/nested/path/test2/xxx1/newname");

// another example call
renameWithNestedMkdir("test1", "test2/xxx1/xxx2");

我将此实现命名为“朴素”，因为在实际生产中，您还应该考虑处理一些边缘情况：如果 $newname 已经存在怎么办？如果 /some/long/nested/path/test2/xxx1 已经存在但它是一个文件（而不是目录）怎么办？为什么我在 mkdir 时放置 0777 访问权限？如果 mkdir 失败怎么办？

Your assumption was correct, this is because "xxx1" in your example does not exist.

So, before rename("oldname", "/some/long/nested/path/test2/xxx1/newname") you have to create directory tree structure: /some/long/nested/path/test2/xxx1/ but newname file (or directory) must not exist at the moment of rename function call.

To generalize the solution look at the following naive function:

function renameWithNestedMkdir($oldname , $newname)
{
     $targetDir = dirname($newname); // Returns a parent directory's path (operates naively on the input string, and is not aware of the actual filesystem)

    // here $targetDir is "/some/long/nested/path/test2/xxx1"
    if (!file_exists($targetDir)) {
        mkdir($targetDir, 0777, true); // third parameter "true" allows the creation of nested directories
    }

    return rename($oldname , $newname);
}

// example call
renameWithNestedMkdir("oldname", "/some/long/nested/path/test2/xxx1/newname");

// another example call
renameWithNestedMkdir("test1", "test2/xxx1/xxx2");

I named this implementation "naive" because in real production you should also think about handling some edge cases: what if $newname already exists? What if /some/long/nested/path/test2/xxx1 already exists but it's a file (not a directory)? Why I put 0777 access rights while mkdir? What if mkdir failed?

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