如何在MATLAB中将灰度矩阵转换为RGB矩阵?

发布于 2024-08-28 20:51:25 字数 156 浏览 6 评论 0原文

rgbImage = grayImage / max(max(grayImage));

或者

rgbImage = grayImage / 255;

以上哪项是正确的,有理由吗?

rgbImage = grayImage / max(max(grayImage));

or

rgbImage = grayImage / 255;

Which of the above is right,and reason?

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情何以堪。 2024-09-04 20:51:25

转换灰度图像RGB 图像,您必须解决两个问题:

  • 灰度图像是二维的,而RGB 图像 是 3-D 的,因此您必须将灰度图像数据复制三次,并将三个副本沿第三个维度连接起来。
  • 图像数据可以存储在许多不同的数据类型中,因此您可以相应地转换它们。当存储为 double 数据类型时,图像像素值应为 0 到 1 范围内的浮点数。当存储为 uint8 数据类型,图像像素值应为 0 到 255 范围内的整数。您可以使用函数

以下是您可能会遇到的 3 种典型情况:

  • 要转换 uint8double 灰度图像转换为相同数据类型的RGB图像,您可以使用函数repmat

    rgbImage = repmat(grayImage,[1 1 3]);
    rgbImage = cat(3,grayImage,grayImage,grayImage);
    
  • 转换 uint8 灰度图像到 double RGB 图像,您应该转换为 先加倍,然后缩放 255:

    rgbImage = repmat(double(grayImage)./255,[1 1 3]);
    
  • 要转换 < code>double 灰度图像到 uint8 RGB 图像,应先缩放 255,然后转换为 uint8

    rgbImage = repmat(uint8(255.*grayImage),[1 1 3]);
    

To convert a grayscale image to an RGB image, there are two issues you have to address:

  • Grayscale images are 2-D, while RGB images are 3-D, so you have to replicate the grayscale image data three times and concatenate the three copies along a third dimension.
  • Image data can be stored in many different data types, so you have to convert them accordingly. When stored as a double data type, the image pixel values should be floating point numbers in the range of 0 to 1. When stored as a uint8 data type, the image pixel values should be integers in the range of 0 to 255. You can check the data type of an image matrix using the function class.

Here are 3 typical conditions you might encounter:

  • To convert a uint8 or double grayscale image to an RGB image of the same data type, you can use the functions repmat or cat:

    rgbImage = repmat(grayImage,[1 1 3]);
    rgbImage = cat(3,grayImage,grayImage,grayImage);
    
  • To convert a uint8 grayscale image to a double RGB image, you should convert to double first, then scale by 255:

    rgbImage = repmat(double(grayImage)./255,[1 1 3]);
    
  • To convert a double grayscale image to a uint8 RGB image, you should scale by 255 first, then convert to uint8:

    rgbImage = repmat(uint8(255.*grayImage),[1 1 3]);
    
原谅过去的我 2024-09-04 20:51:25

根据定义,RGB 图像有 3 个通道,这意味着您需要一个三维矩阵来表示图像。因此,正确的答案是:

rgbImage = repmat(255*grayImage/max(grayImage(:)),[1 1 3]);

规范化 GrayImage 时要小心。如果grayImageuint8,那么您将在255*grayImage/max(grayImage(:))操作中丢失一些精度。

此外,归一化grayImage取决于数据。在您的问题中,您使用了两种方法:

rgbImage = grayImage / max(max(grayImage));

对灰度图像进行标准化,使图像中的最大值为 1 ,并且

rgbImage = grayImage / 255;

仅当 grayImage 中的值位于0-255 范围。

所以这实际上取决于你想做什么。但是,如果您想要 RGB 图像,则需要将单通道矩阵转换为 3 通道矩阵。

By definition, an RGB image has 3 channels, which implies you need a three-dimensional matrix to represent the image. So, the right answer is:

rgbImage = repmat(255*grayImage/max(grayImage(:)),[1 1 3]);

Be careful when normalizing grayImage. If grayImage is uint8 then you will lose some precision in the 255*grayImage/max(grayImage(:)) operation.

Also, normalizing grayImage depends on the data. In your question, you used two methods:

rgbImage = grayImage / max(max(grayImage));

which normalizes the grayscale image such that the maximum value in the image is 1 and

rgbImage = grayImage / 255;

which only makes sense if the values in grayImage lie in the 0-255 range.

So it really depends on what you want to do. But, if you want an RGB image you need to convert your single-channel matrix to a 3-channel matrix.

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