用户所属的wmi组

发布于 2024-08-28 11:24:23 字数 497 浏览 4 评论 0原文

我有找到所有本地用户的代码：

        ManagementObjectSearcher userSearcher = new ManagementObjectSearcher("SELECT * FROM Win32_UserAccount");
        foreach (ManagementObject user in userSearcher.Get())
        {
            if ((bool)user["LocalAccount"])
            {
                string UserName = (string)user["Name"];
            }
        }
        return;

现在我想要帮助我选择用户所在的所有组的代码。我知道有一个名为 Win32_GroupUser 的表，我必须使用 PartComponent 来指示用户名，但我无法创建查询。请帮忙提供有关 WQL 的信息。

原文

i have the code which find all local users:

        ManagementObjectSearcher userSearcher = new ManagementObjectSearcher("SELECT * FROM Win32_UserAccount");
        foreach (ManagementObject user in userSearcher.Get())
        {
            if ((bool)user["LocalAccount"])
            {
                string UserName = (string)user["Name"];
            }
        }
        return;

now i want code which help me to select all groups in which user consist. I know that there is table called Win32_GroupUser and i must use PartComponent to indicate user name but i cant create query. Please help with information about WQL.

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花伊自在美 2024-09-04 11:24:23

查询将类似于：

select * from Win32_GroupUser 
       WHERE PartComponent="Win32_Group.Domain='Workgroup',Name='LocalAccount'" 

string query = "Select * from Win32_GroupUser Where PartComponent=";
query += '"Win32_Group.Domain=';
query += "'" + user["Domain"] + "'";
query += ",Name='" + user["Name"] + "'";
query += '"';

您需要传递域名和用户名来查找关联的组。出于性能原因，我推荐 StringBuilder 类。

我从这篇文章中得出这个答案。

The query will look something like:

select * from Win32_GroupUser 
       WHERE PartComponent="Win32_Group.Domain='Workgroup',Name='LocalAccount'" 

string query = "Select * from Win32_GroupUser Where PartComponent=";
query += '"Win32_Group.Domain=';
query += "'" + user["Domain"] + "'";
query += ",Name='" + user["Name"] + "'";
query += '"';

You need to pass the domain name and username to lookup the associated groups. For performance reasons I would recommend StringBuilder class.

I derived this answer from this article.

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