从 .NET 调用非托管代码

发布于 2024-08-28 07:56:59 字数 1905 浏览 6 评论 0原文

我正在尝试在我的 C# 程序中使用 dll，但我似乎无法让它工作。我制作了一个测试应用程序，如下所示。返回值是 0，但它实际上并没有做它应该做的事情。

而以下命令确实有效：

rundll32 cmproxy.dll,SetProxy /source_filename proxy-1.txt /backup_filename roxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /Profile "C:\Documents and ettings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp"

代码：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Security.Cryptography;
using System.Runtime.InteropServices;
using System.Net;
using WUApiLib;

namespace nac
{
    class Program
    {
        [DllImport("cmproxy.dll", CharSet = CharSet.Unicode)]
        static extern int SetProxy(string cmdLine);

        static void Main(string[] args)
        {
            string cmdLine = @"/source_filename proxy-1.txt /backup_filename proxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /Profile ""C:\Documents and Settings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp""";
            Console.WriteLine(SetProxy(cmdLine));
        }
    }
}

这是 dumpbin /exports 命令的内容

File Type: DLL

  Section contains the following exports for cmproxy.dll

    00000000 characteristics
    3E7FEF8C time date stamp Tue Mar 25 05:56:28 2003
        0.00 version
           1 ordinal base
           1 number of functions
           1 number of names

    ordinal hint RVA      name

          1    0 00001B68 SetProxy

  Summary

        1000 .data
        1000 .reloc
        1000 .rsrc
        2000 .text

当此命令有效时，它会设置 VPN 连接的代理服务器。

编辑：

我希望避免从 system.process 运行 rundll32

我还可以提供 dll 和我的测试应用程序的链接。尽管上面粘贴的代码是它所包含的全部内容，并且我认为该 dll 可以从服务器资源工具包中获得。

更新：

我用 c++ 编写了一个测试 DLL，它只是回显给定的参数。它正在运行，但它说

句柄无效

原文

I am trying to use a dll in my c# program but I just cant seem to get it to work. I have made a test app shown below. The return value is 0, however it does not actually do what it is supposed to do.

Whereas the following command does work:

rundll32 cmproxy.dll,SetProxy /source_filename proxy-1.txt /backup_filename roxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /Profile "C:\Documents and ettings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp"

Code:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Security.Cryptography;
using System.Runtime.InteropServices;
using System.Net;
using WUApiLib;

namespace nac
{
    class Program
    {
        [DllImport("cmproxy.dll", CharSet = CharSet.Unicode)]
        static extern int SetProxy(string cmdLine);

        static void Main(string[] args)
        {
            string cmdLine = @"/source_filename proxy-1.txt /backup_filename proxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /Profile ""C:\Documents and Settings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp""";
            Console.WriteLine(SetProxy(cmdLine));
        }
    }
}

Here is the contents of the dumpbin /exports command

File Type: DLL

  Section contains the following exports for cmproxy.dll

    00000000 characteristics
    3E7FEF8C time date stamp Tue Mar 25 05:56:28 2003
        0.00 version
           1 ordinal base
           1 number of functions
           1 number of names

    ordinal hint RVA      name

          1    0 00001B68 SetProxy

  Summary

        1000 .data
        1000 .reloc
        1000 .rsrc
        2000 .text

When this works it sets the proxy server for a VPN connection.

EDIT:

I wish to avoid running rundll32 from system.process

I can also provide a link to both the dll and my test app. Although the code pasted above is all it contains and the dll is available from the Server resource kit I think.

UPDATE:

I have written a test DLL in c++ that simply echos the args it is given. It is running but it says

The handle is invalid

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笨笨の傻瓜 2024-09-04 07:56:59

只是一些值得深思的东西。这可能是一个可能的解决方法。

也许您可以使用 System.Diagnostics.Process 类从代码中运行命令，如下所示：

  System.Diagnostics.Process p = new System.Diagnostics.Process();
  p.StartInfo.Arguments = @"cmproxy.dll,SetProxy /source_filename proxy-1.txt /backup_filename roxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /Profile ""C:\Documents and ettings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp\""";
  p.StartInfo.FileName = "rundll32";
  p.Start();

如果您需要在运行时替换某些参数，那么您可以使用 String.Format 来格式化参数并替换您需要的任何内容。

编辑1：

这里似乎没有正确突出显示代码。我没有 cmproxy.dll，因此无法测试此场景。

Just some food for thought. This may be a possible work around.

Perhaps you could use the System.Diagnostics.Process class to run the command from your code like this:

  System.Diagnostics.Process p = new System.Diagnostics.Process();
  p.StartInfo.Arguments = @"cmproxy.dll,SetProxy /source_filename proxy-1.txt /backup_filename roxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /Profile ""C:\Documents and ettings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp\""";
  p.StartInfo.FileName = "rundll32";
  p.Start();

If you need to substitute some of the arguments at runtime then you could use String.Format to format the arguments and substitute whatever you need.

Edit 1:

It doesn't seem to be correctly highlighting the code here. I don't have cmproxy.dll so I cannot test this scenario.

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欢你一世 2024-09-04 07:56:59

也许有关 RUNDLL32.EXE 的 Microsoft 文档会有所帮助？特别是，本节似乎很有用：

Rundll 条目的参数
要点如下：

hwnd - 应该用作所有者窗口的窗口句柄您的 DLL 创建的任何窗口 hinst - 你的 DLL 实例句柄 lpszCmdLine - DLL 应该解析的 ASCIIZ 命令行 nCmdShow - 描述 DLL 的窗口应如何显示

在以下示例中：

<前> RUNDLL.EXE SETUPX.DLL,InstallHinfSection 132 C:\WINDOWS\INF\SHELL.INF

Rundll 将调用 InstallHinfSection() 入口点 Setupx.dll 中的函数并将其传递给以下参数：

 hwnd = (父窗口句柄)
   hinst = SETUPX.DLL 的实例
   lpszCmdLine = "132 C:\WINDOWS\INF\SHELL.INF"
   nCmdShow =（无论 nCmdShow 传递给 CreateProcess 是什么）

更新 2：

这应该适合您：

[DllImport("cmproxy.dll", SetLastError = true, CharSet = CharSet.Unicode)] 
static extern void SetProxy(IntPtr hwnd, IntPtr hinst, string lpszCmdLine, int nCmdShow);

然后像这样调用它：

const int SW_SHOWNORMAL = 1;
IntPtr hWnd = (this as Form).Handle;
IntPtr hInstance = Marshal.GetHINSTANCE(this.GetType().Module);
SetProxy(hWnd, hInstance, cmdLine, SW_SHOWNORMAL);

我使用 shell32.dll 中的 Control_RunDLL 入口点测试了相同的代码，我可以确认它对我来说工作正常。诀窍是获取正确的 HWND 和 HINSTANCE 指针作为前两个参数传递。另外，我之前为 nCmdShow 传递了 0，但是根据 pinvoke.net< /a>，SW_SHOWNORMAL 的值为 1，这可能就是您想要的。

Perhaps the Microsoft documentation on RUNDLL32.EXE would be helpful? In particular, this section seems useful:

The parameters to the Rundll entry
point are as follows:

   hwnd - window handle that should be used as the owner window for
          any windows your DLL creates
   hinst - your DLL's instance handle
   lpszCmdLine - ASCIIZ command line your DLL should parse
   nCmdShow - describes how your DLL's windows should be displayed

In the following example:

     RUNDLL.EXE SETUPX.DLL,InstallHinfSection 132 C:\WINDOWS\INF\SHELL.INF

Rundll would call the InstallHinfSection() entrypoint
function in Setupx.dll and pass it the
following parameters:

   hwnd = (parent window handle)
   hinst = HINSTANCE of SETUPX.DLL
   lpszCmdLine = "132 C:\WINDOWS\INF\SHELL.INF"
   nCmdShow = (whatever the nCmdShow was passed to CreateProcess)

Update 2:

This should work for you:

[DllImport("cmproxy.dll", SetLastError = true, CharSet = CharSet.Unicode)] 
static extern void SetProxy(IntPtr hwnd, IntPtr hinst, string lpszCmdLine, int nCmdShow);

and then call it like:

const int SW_SHOWNORMAL = 1;
IntPtr hWnd = (this as Form).Handle;
IntPtr hInstance = Marshal.GetHINSTANCE(this.GetType().Module);
SetProxy(hWnd, hInstance, cmdLine, SW_SHOWNORMAL);

I tested the same code with the Control_RunDLL entrypoint in shell32.dll and I can confirm that it works fine for me. The trick is getting the correct HWND and HINSTANCE pointers to pass in as the first two arguments. Also, I was previously passing 0 for the nCmdShow, but according to pinvoke.net, SW_SHOWNORMAL has value 1, which is probably what you want.

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