PHP下载文件最简单的方法是什么
我需要从某个 URL 下载图像到我的服务器。但是，我的服务器的配置不允许我这样做：
getimagesize( $file );
因为，它会生成错误：
Warning: getimagesize() [function.getimagesize]: URL file-access is disabled in the server configuration in somefile.php on line 10
那么，我是否可以使用另一种不需要外部库的方法？
好的，我用 OIS 的解决方案解决了这个问题：
$filename = '/tmp/'.md5($file);
$ch = curl_init($file);
$fp = fopen($filename, "w");
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
curl_close($ch);
fclose($fp);
$ext = getimagesize( $filename );
I need to download an image from some URL to my server. However, my server's config disallowed me to do it this way:
getimagesize( $file );
Because, it generate error:
Warning: getimagesize() [function.getimagesize]: URL file-access is disabled in the server configuration in somefile.php on line 10
So, is there another way I can use that doesn't require external library?
Ok, I solved it with solution from OIS:
$filename = '/tmp/'.md5($file);
$ch = curl_init($file);
$fp = fopen($filename, "w");
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
curl_close($ch);
fclose($fp);
$ext = getimagesize( $filename );
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您可以尝试 curl。
You can try curl.
除非修改服务器配置，否则不可能
it is not possible unless you modify the server configuration
如果您的服务器上禁用了对 URL 的文件访问，则您无法从外部 URL 加载任何内容。这就是该配置的目的。
在未禁用它的服务器上，file_get_contents($url) 是获取大多数文件的最简单方法。
If file access to URLs is disabled on your server, you can't load any content from external URLs. That's the purpose of that configuration.
On a server where it's not disabled, file_get_contents($url) is the easiest way to fetch most files.
使用以下命令将文件下载到
$imgdata中。然后您可以将其保存到文件并获取其图像大小。您可能可以通过一些工作来删除文件保存步骤，以使其更快。Use the following to download the file into
$imgdata. You can then save it to a file and get its image size. You can probably remove the file saving step with a bit of work to make it faster.