错误“以 10 为基数的 int() 的文字无效：”不断出现
我正在尝试编写一个非常简单的程序，我想打印出低于 100 的 3 和 5 的所有倍数之和，但是，错误不断出现，提示“以 10 为基数的 int() 的文字无效：”程序如下：
sum = ""
sum_int = int(sum)
for i in range(1, 101):
if i % 5 == 0:
sum += i
elif i % 3 == 0:
sum += i
else:
sum += ""
print sum
任何帮助将不胜感激。
I'm trying to write a very simple program, I want to print out the sum of all the multiples of 3 and 5 below 100, but, an error keeps accuring, saying "invalid literal for int() with base 10:" my program is as follows:
sum = ""
sum_int = int(sum)
for i in range(1, 101):
if i % 5 == 0:
sum += i
elif i % 3 == 0:
sum += i
else:
sum += ""
print sum
Any help would be much appreciated.
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评论（3）
""是导致这些问题的原因。更改
为
并摆脱
The
""are the cause of these problems.Change
to
and get rid of
Python 不是 JavaScript：
""不会自动转换为0，0也不会自动转换为"0".您的程序似乎还混淆了打印三和五的所有倍数的总和以及打印三和五的倍数的所有数字的列表。
Python is not JavaScript:
""does not automatically convert to0, and0does not automatically convert to"0".Your program also seems to be confused between printing the sum of all the multiples of three and five and printing a list of all the numbers which are multiples of three and five.
好吧，我是 Python 新手，所以我做了很多愚蠢的事情；不管怎样，我想我现在已经解决了。
Ok, I'm new to Python so I was doing quite a few silly things; anyway, I think I've worked it out now.