如何使用休眠将一些实体的值存储在另一个表中？

发布于 2024-08-27 11:20:49 字数 802 浏览 7 评论 0原文

有没有一种简单的方法可以使用 hibernate 将某些字段保留在另一个类和表中。

例如，我有一个包含 name、surname、email、address1 的 Person 类>、地址2、城市、国家字段。我希望我的课程是：

public class Person
{
   private String name;
   private String surname;
   private String email;
   private Address address;
   // ..
}

public class Address
{
   private Person person; // to whom this belongs
   private String address1;
   private String address2;
   private String city;
   private String country;
   // ..
}

我想将地址存储在另一个表中。实现这一目标的最佳方法是什么？

编辑：我正在使用注释。它不一定是我所描述的方式，我正在寻找最佳实践。

编辑 2： 地址的 ID 是什么？

附言。如果有一种方法可以使 Address 不可变（用作值对象）那就更好了，或者可能不是，因为我从错误的角度思考一切:)

原文

is there a simple way to persist some of the fields in another class and table using hibernate.

For example, I have a Person class with name, surname, email, address1, address2, city, country fields. I want my classes to be:

public class Person
{
   private String name;
   private String surname;
   private String email;
   private Address address;
   // ..
}

public class Address
{
   private Person person; // to whom this belongs
   private String address1;
   private String address2;
   private String city;
   private String country;
   // ..
}

and I want to store Address in another table. What is the best way to achieve this?

Edit: I am using annotations. It does not have to be the way I described, I am looking for best practices.

Edit 2: What will be the Id of Address?

PS. If there is a way to make Address immutable (to use as a value object) that is even better, or maybe not because I thought everything from wrong perspective :)

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哆兒滾 2024-09-03 11:20:49

将 Address 映射为实体并添加主键（自动生成的 ID）
将 Person 和 Address 之间的关系映射为 one -to-one（每个字段上的@OneToOne）

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或十年 2024-09-03 11:20:49

使用 Hibernate 3.5 可以定义外部生成器（又名 JPA 映射），详细信息为此处。

这是非常简单的 Person 应该实现 Serialized 然后将 @Id 注释添加到 person 中。

@Entity
@AccessType(value = "field")
@Table(name = "addresses")
public class Address
{
   @Id
   @OneToOne
   @JoinColumn(name = "person_id")
   private Person person;
   // ...
}

还有一个替代方案，但我真的很喜欢第一个：

@Entity
@AccessType(value = "field")
@Table(name = "addresses")
public class Address
{
   @Id
   private int personId;

   @MapsId
   @OneToOne
   @JoinColumn(name = "person_id")
   private Person person;
   // ...
}

With Hibernate 3.5 it is possible to define foreign generators (aka. JPA mapping), details are here.

It is pretty straight forward Person should implement Serializable then @Id annotation is added to person.

@Entity
@AccessType(value = "field")
@Table(name = "addresses")
public class Address
{
   @Id
   @OneToOne
   @JoinColumn(name = "person_id")
   private Person person;
   // ...
}

There is an alternative but I really like the first one:

@Entity
@AccessType(value = "field")
@Table(name = "addresses")
public class Address
{
   @Id
   private int personId;

   @MapsId
   @OneToOne
   @JoinColumn(name = "person_id")
   private Person person;
   // ...
}

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