如何查找和更改 n 与 n 之间的乘法类n
我有一些表结构:
<tr class="row-2"><tr>
<tr class="row-3">..<tr>
<tr class="row-4">..<tr>
<tr class="row-5">..<tr>
<tr class="row-6">..<tr>
<tr class="row-7"><tr>
<tr class="row-8">..<tr>
<tr class="row-9">..<tr>
<tr class="row-10">..<tr>
<tr class="row-11">..<tr>
...etc
对于此示例,具有类“row-2”和“row-7”的 TR 是展开子行的父产品链接。
<script>
$(function() {
$('tr.parent')
.css("cursor","pointer")
.css("color","red")
.attr("title","Click to expand/collapse")
.click(function(){
$(this).siblings('.child-'+this.id).toggle();
});
$('tr[@class^=child-]').hide().children('td');
});
</script>
行 -3...-6 是行 2 的子行 和 行-8...-11是行7的子行
我怎样才能找到行2,行7等,然后添加第二类“父”和ID类似的类(id =“row” -2”、id=“row-7”等)?另外,我需要在 row-2 和 row-7 类之间添加等于上一个父行的每个 TR 。归根结底,我需要这样的东西:
<tr class="row-2 parent" id="row-2"><tr>
<tr class="row-3 child-row2">..<tr>
<tr class="row-4 child-row2">..<tr>
<tr class="row-5 child-row2">..<tr>
<tr class="row-6 child-row2">..<tr>
<tr class="row-7 parent" id="row-7"><tr>
<tr class="row-8 child-row7">..<tr>
<tr class="row-9 child-row7">..<tr>
<tr class="row-10 child-row7">..<tr>
<tr class="row-11 child-row7">..<tr>
..etc
I have some table structure:
<tr class="row-2"><tr>
<tr class="row-3">..<tr>
<tr class="row-4">..<tr>
<tr class="row-5">..<tr>
<tr class="row-6">..<tr>
<tr class="row-7"><tr>
<tr class="row-8">..<tr>
<tr class="row-9">..<tr>
<tr class="row-10">..<tr>
<tr class="row-11">..<tr>
...etc
for this example TR with classes "row-2" and "row-7" is parrent product link wich expand child rows.
<script>
$(function() {
$('tr.parent')
.css("cursor","pointer")
.css("color","red")
.attr("title","Click to expand/collapse")
.click(function(){
$(this).siblings('.child-'+this.id).toggle();
});
$('tr[@class^=child-]').hide().children('td');
});
</script>
Rows -3...-6 is child of row-2
and
Rows -8...-11 is child of row-7
How can I find row-2, row-7, etc then add second class "parent" and ID similar class (id="row-2", id="row-7", etc)? Also I need add in each TR between row-2 and row-7 class equal previous parent row. In bottom line I need something like this:
<tr class="row-2 parent" id="row-2"><tr>
<tr class="row-3 child-row2">..<tr>
<tr class="row-4 child-row2">..<tr>
<tr class="row-5 child-row2">..<tr>
<tr class="row-6 child-row2">..<tr>
<tr class="row-7 parent" id="row-7"><tr>
<tr class="row-8 child-row7">..<tr>
<tr class="row-9 child-row7">..<tr>
<tr class="row-10 child-row7">..<tr>
<tr class="row-11 child-row7">..<tr>
..etc
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
一种方法是对所有行执行两次传递,以设置所需的类和 ID。在第一遍中,添加与类名相同的 id,并将
parent
类添加到 row-2 和 row-7。在第二遍中,找到每个.parent
行,并将child-
类添加到其同级,直到下一个父级。这不是对 row-2 和 row-7 的值进行硬编码,而是假设所有标头项都包含在元素内,而不是
< /代码> 元素。
这是一些代码: http://jsfiddle.net/vYTW2/
One way is to do a two-pass on all rows, to set up the required classes and id's. In the first pass, add an id same as the class name, and also add the
parent
class to row-2, and row-7. In the second pass, find each.parent
row, and addchild-<id>
class to their siblings until the next parent. Instead of hard-coding the values for row-2 and row-7, this assumes that all header items are contained inside a<th>
element, instead of a<td>
element.Here's some code: http://jsfiddle.net/vYTW2/