使用 preg_match_all() 和结束字符匹配一个字符串中的多个项目

Question

我有以下代码：

preg_match_all('/(.*) \((\d+)\) - ([\d\.\d]+)[,?]/U',
    "E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15",
    $match);
var_dump($string, $match);

并获得以下输出：

array(4) {
  [0]=>
  array(1) {
    [0]=>
    string(54) "E-Book What I Didn't Learn At School... (2) - 3525.01,"
  }
  [1]=>
  array(1) {
    [0]=>
    string(39) "E-Book What I Didn't Learn At School..."
  }
  [2]=>
  array(1) {
    [0]=>
    string(1) "2"
  }
  [3]=>
  array(1) {
    [0]=>
    string(7) "3525.01"
  }
}

仅匹配一项...我需要的是从此类字符串中获取所有项目。当我在字符串末尾添加“，”符号时 - 它工作得很好。但这在每个字符串中添加逗号是没有意义的。有什么建议吗？

Answer 1

试试这个正则表达式：

(.*?)\s*\((\d+)\)\s*-\s*(\d+\.\d+)(?:,\s*)?

主要的区别是你有 .* （贪婪），我用 .*? （非贪婪）替换。您首先“吃掉”整个字符串（除了换行符），然后回溯以仅匹配字符串中的一个片段。

演示：

preg_match_all('/(.*?)\s*\((\d+)\)\s*-\s*(\d+\.\d+)(?:,\s*)?/',
    "E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15",
    $matches, PREG_SET_ORDER);
print_r($matches);

产生：

Array
(
    [0] => Array
        (
            [0] => E-Book What I Didn't Learn At School... (2) - 3525.01, 
            [1] => E-Book What I Didn't Learn At School...
            [2] => 2
            [3] => 3525.01
        )

    [1] => Array
        (
            [0] => FREE Intro DVD/Vid (1) - 0.15
            [1] => FREE Intro DVD/Vid
            [2] => 1
            [3] => 0.15
        )

)