按角度查找坐标

发布于 2024-08-27 06:24:23 字数 577 浏览 7 评论 0原文

我正在 XNA 中开发绘制随机路径的应用程序。不幸的是，我对图表不太了解，所以我有点卡住了。我的应用程序需要执行以下操作：

从原点 (0,0) 选取一个随机角度，这很简单。
以上面找到的角度，相对于原点 16 像素（或我指定的任何距离）绘制一个圆。

（请原谅我糟糕的照片处理）

(16,16) 处的第二个圆代表距原点 16 个像素的 45 度角。

我想要一种方法，在其中传递我的距离和角度，返回一个点到图形处。即

private Point GetCoordinate(float angle, int distance)
{
   // Do something.
   return new Point(x,y);
}

我知道这很简单，但同样，我对绘图非常不了解。有什么帮助吗？

谢谢，乔治

原文

I am developing in application in XNA which draws random paths. Unfortunately, I'm out of touch with graphing, so I'm a bit stuck. My application needs to do the following:

Pick a random angle from my origin (0,0), which is simple.
Draw a circle in relation to that origin, 16px away (or any distance I specify), at the angle found above.

(Excuse my horrible photoshoping)

alt text http://www.refuctored.com/coor.png

The second circle at (16,16) would represent a 45 degree angle 16 pixels away from my origin.

I would like to have a method in which I pass in my distance and angle that returns a point to graph at. i.e.

private Point GetCoordinate(float angle, int distance)
{
   // Do something.
   return new Point(x,y);
}

I know this is simple, but agian, I'm pretty out of touch with graphing. Any help?

Thanks,
George

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￠好甜 2024-09-03 06:24:23

如果角度以度为单位，则首先执行：

angle *= Math.PI / 180;

然后：

return new Point(distance * Math.Cos(angle), distance * Math.Sin(angle));

顺便说一句，(16, 16) 处的点距离原点不是 16 个像素，而是 sqrt(16^2 + 16^2) = sqrt(512) = 〜22.63 像素。

If the angle is in degrees, first do:

angle *= Math.PI / 180;

Then:

return new Point(distance * Math.Cos(angle), distance * Math.Sin(angle));

By the way, the point at (16, 16) is not 16 pixels away from the origin, but sqrt(16^2 + 16^2) = sqrt(512) =~ 22.63 pixels.

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君勿笑 2024-09-03 06:24:23

private Point GetCoordinate(float angle, int distance)
{
  float x = cos(angle) * distance;
  float y = sin(angle) * distance;
  return new Point(x, y);
}

请注意，三角函数可能采用弧度。如果角度以度为单位，请除以 180/Pi。

private Point GetCoordinate(float angle, int distance)
{
  float x = cos(angle) * distance;
  float y = sin(angle) * distance;
  return new Point(x, y);
}

Note that the trigonometric functions probably take radians. If your angle is in degrees, divide by 180/Pi.

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