ASP.NET MVC post 模型的示例？

发布于 2024-08-26 19:38:00 字数 229 浏览 3 评论 0原文

我正在观看关于 MIX 的 ASP.NET MVC 的 HaHaa 演示，他们提到使用帖子模型，我猜他们是说您可以使用仅用于发布的模型。我曾尝试寻找这方面的例子。我不明白他们在说什么吗？有谁有一个例子说明这如何在强类型视图中工作，其中视图模型和帖子模型不是同一类型？

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忘羡 2024-09-02 19:38:00

下面是 ScottGu 的示例，稍作扩展。正如 @SLaks 所解释的，当收到 POST 时，MVC 将尝试创建一个新的 MyPostName 对象并将其属性与 from 字段相匹配。它还将使用匹配和验证的结果更新 ModelState 属性。

当操作返回视图时，它也必须为其提供模型。但是，视图不必使用相同的模型。事实上，视图可以使用包含扩展数据的不同模型进行强类型化，例如，它可以将导航属性绑定到数据库表中的外部键；如果是这种情况，从 POST 模型映射到视图模型的逻辑将包含在 POST 操作中。

public class MyGetModel
{
    string FullName;
    List<MyGetModel> SuggestedFriends;
}

public class MyPostModel
{
    string FirstName;
    string LastName;
}

//GET: /Customer/Create
public ActionResult Create()
{
    MyGetModel myName = new MyGetModel();
    myName.FullName = "John Doe"; // Or fetch it from the DB
    myName.SuggestedFriends = new List<MyGetModel>; // For example - from people select name where name != myName.FullName
    Model = myName;
    return View();
}

//POST: /Customer/Create
[HttpPost]
public ActionResult Create(MyPostModel newName)
{
    MyGetModel name = new MyGetModel();
    name.FullName = newName.FirstName + "" + newName.LastName; // Or validate and update the DB 
    return View("Create", name);
}

Below is ScottGu's example expanded a bit. As @SLaks explained, when the POST is received, MVC will try to create a new MyPostName object and match its properties with the from fields. It will also update the ModelState property with the results of the matching and validation.

When the action returns the view, it has to provide a model for it as well. However, the view doesn't have to use that same model. In fact, the view can be strongly typed with a different model, that contains the expanded data, for example it can have navigation properties bound to external keys in the DB table; and if that's the case, the logic to map from the POST model to the view model will be contained in the POST action.

public class MyGetModel
{
    string FullName;
    List<MyGetModel> SuggestedFriends;
}

public class MyPostModel
{
    string FirstName;
    string LastName;
}

//GET: /Customer/Create
public ActionResult Create()
{
    MyGetModel myName = new MyGetModel();
    myName.FullName = "John Doe"; // Or fetch it from the DB
    myName.SuggestedFriends = new List<MyGetModel>; // For example - from people select name where name != myName.FullName
    Model = myName;
    return View();
}

//POST: /Customer/Create
[HttpPost]
public ActionResult Create(MyPostModel newName)
{
    MyGetModel name = new MyGetModel();
    name.FullName = newName.FirstName + "" + newName.LastName; // Or validate and update the DB 
    return View("Create", name);
}

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