Cygwin bash 语法错误 - 但脚本在 Ubuntu 中运行良好

发布于 2024-08-26 19:08:32 字数 726 浏览 4 评论 0原文

#!/bin/bash
if test "$#" == "4"; then echo "$*"; else echo "args-error" >&2; fi;

当我尝试在 Ubuntu 和 Cygwin 上运行这个小代码片段时，它给我带来了很多麻烦。

Ubuntu 运行 bash 版本 4.0+，而 Cygwin 运行 3.2.49；但我认为版本冲突不是造成这种情况的原因，这段代码在 fedora 10 下运行良好，它也使用 bash 版本 3.+

所以基本上我想知道是否有一种方法可以一劳永逸地编写我的脚本，所以有以后就不会再遇到这个可怕的问题了。

非常感谢。

编辑：我目前手头没有 Cygwin，但从我的记忆来看，它一直在说类似无法解析未定义的令牌“fi”之类的内容。

编辑：嗯，原始形式是这样的，刚刚从服务器找到：

#!/bin/bash
if ["$#" == "4"];
    then echo "$*";
    else echo "args-error" >&2;
fi;

控制台抱怨：

$ ./test.sh 1 2 3
./test.sh: line 2: [3: command not found
args-error

我也想知道为什么 stderr 说出了问题 - 命令未找到 - 但仍然可以打印出答案？

原文

#!/bin/bash
if test "$#" == "4"; then echo "$*"; else echo "args-error" >&2; fi;

This little code snippet troubles me a lot when I tried to run it on both Ubuntu and Cygwin.

Ubuntu runs bash version 4.0+ whereas Cygwin runs 3.2.49; But I reckon version collision shall not be the cause of this, this code runs well under fedora 10 which is also using bash version 3.+

So basically I am wondering if there is a way to code my script once and for all so there are not to have this awful issue later on.

Many thanks in advance.

Edited : I don't have Cygwin by hand at the moment but from my memory, it keeps saying something like couldn't resolve undefined token "fi" something like that.

Edited : well,the original form is like this, just found from server :

#!/bin/bash
if ["$#" == "4"];
    then echo "$*";
    else echo "args-error" >&2;
fi;

Console complains :

$ ./test.sh 1 2 3
./test.sh: line 2: [3: command not found
args-error

I am also wondering how come that stderr says something goes wrong - command not found - but can still print out the answer?

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困倦 2024-09-02 19:08:32

[ 和 ] 周围需要空格。

#!/bin/bash
if [ "$#" == "4" ];
    then echo "$*";
    else echo "args-error" >&2;
fi;

You need whitespace around the [ and ].

#!/bin/bash
if [ "$#" == "4" ];
    then echo "$*";
    else echo "args-error" >&2;
fi;

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只等公子 2024-09-02 19:08:32

更新的答案：

您需要在 [ 之后有一个空格，否则 ["$#" 被评估为例如不存在的 [3 。试试这个：

if [ "$#" == "4" ];
    then echo "$*";
    else echo "args-error" >&2;
fi;

它对我有用。我猜您会收到这样的错误：

test.sh: line 2: 
发生这种情况是因为您使用 Windows 样式的行结尾编辑了文件，但 Bash 需要 Unix 样式的行结尾。要修复该文件，请尝试运行以下命令：
dos2unix test.sh

您当然需要将文件名更改为脚本的实际文件名。
\r': command not found
test.sh: line 3: 
发生这种情况是因为您使用 Windows 样式的行结尾编辑了文件，但 Bash 需要 Unix 样式的行结尾。要修复该文件，请尝试运行以下命令：

您当然需要将文件名更改为脚本的实际文件名。
\r': command not found

发生这种情况是因为您使用 Windows 样式的行结尾编辑了文件，但 Bash 需要 Unix 样式的行结尾。要修复该文件，请尝试运行以下命令：

您当然需要将文件名更改为脚本的实际文件名。

Updated answer:

You need a space after [ otherwise ["$#" is evaluated to for example [3 which doesn't exist. Try this:

if [ "$#" == "4" ];
    then echo "$*";
    else echo "args-error" >&2;
fi;

It works for me. I would guess that you are getting an error like this:

test.sh: line 2: 
This can happen because you have edited the file using Windows-style line endings but Bash expects Unix-style line endings. To fix the file, try running this command:
dos2unix test.sh

You of course need to change the filename to the actual filename of your script.
\r': command not found
test.sh: line 3: 
This can happen because you have edited the file using Windows-style line endings but Bash expects Unix-style line endings. To fix the file, try running this command:

You of course need to change the filename to the actual filename of your script.
\r': command not found

This can happen because you have edited the file using Windows-style line endings but Bash expects Unix-style line endings. To fix the file, try running this command:

You of course need to change the filename to the actual filename of your script.

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