Django：使用 {% url %} 查找视图 URL 的一部分
我无法仅获取带有 {% url %} 标记的 URL 的一部分。
URL 设置包含以下内容：
url("^delete/(?P<uuid>[a-f0-9]{8}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{12})/$",
deleteView,
name = "delete"),
这意味着通过 UUID 删除项目（如您所见，视图采用参数“uuid”）。由于我不想在 URL 映射更改时更改所有模板，因此我使用命名 URL（本例中为“删除”）。
然后在模板中，我想通过 AJAX 访问该 URL，但需要使用 JavaScript 提供 UUID 参数，所以实际上我只需要 URL 的 /delete/ 部分。我当前的解决方案是这样的：
uuid = "some uuid that should be deleted on the server";
$.get("{% url myinstancenamespace:delete "00000000-0000-0000-0000-000000000000" %}"
.replace("00000000-0000-0000-0000-000000000000", uuid),
function(data)
{
// process server response
}, "text");
这对我来说更像是一种黑客攻击。那么，还有比这更好的解决方案吗？
I'm having trouble getting only a part of an URL with the {% url %} tag.
The URL setup contains this:
url("^delete/(?P<uuid>[a-f0-9]{8}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{12})/$",
deleteView,
name = "delete"),
which means to delete an item by its UUID (the view takes a parameter "uuid" as you can see). As I don't want to change all templates when the URL mappings change, I'm using named URLs ("delete" in this example).
Then in the template, I want to access that URL via AJAX but need to provide the UUID parameter using JavaScript, so really I only need the /delete/ part of the URL. My current solution is this:
uuid = "some uuid that should be deleted on the server";
$.get("{% url myinstancenamespace:delete "00000000-0000-0000-0000-000000000000" %}"
.replace("00000000-0000-0000-0000-000000000000", uuid),
function(data)
{
// process server response
}, "text");
This seems more like a hack to me. So, are there any better solutions than this?
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我必须说，这对我来说听起来并不完全是黑客行为。
但如果您确实不想这样做，一种选择是在 URLconf 中将
uuid参数设置为可选，方法是在其前面加上?:前缀。当然，您需要在视图中进行更多验证，以确保您确实拥有 uuid。It doesn't sound completely hackish to me, I must say.
But if you really don't want to do it like that, one option would be to make the
uuidparameter optional in the URLconf, by prefixing it with?:. Of course you'd then need to do a bit more validation in the view to ensure that you actually did have a uuid.