如何将部分视图渲染为字符串

Question

我有以下代码：

public ActionResult SomeAction()
{
    return new JsonpResult
    {
        Data = new { Widget = "some partial html for the widget" }
    };
}

我想修改它，以便我可以

public ActionResult SomeAction()
{
    // will render HTML that I can pass to the JSONP result to return.
    var partial = RenderPartial(viewModel); 
    return new JsonpResult
    {
        Data = new { Widget = partial }
    };
}

这样做吗？有人可以解释一下怎么做吗？

注意，我在发布解决方案之前编辑了问题。

Answer 1

我为 ASP.NET MVC 4 应用程序选择了如下扩展方法。我认为它比我见过的一些建议更简单：

public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

它允许我执行以下操作：

var html = PartialView("SomeView").RenderToString();

此外，此方法会保留任何 Model、ViewBag 和其他视图数据的观点。

Answer 2

这是一个有效答案的稍微修改版本：

public static string RenderPartialToString(string controlName, object viewData)
{
    ViewPage viewPage = new ViewPage() { ViewContext = new ViewContext() };

    viewPage.ViewData = new ViewDataDictionary(viewData);
    viewPage.Controls.Add(viewPage.LoadControl(controlName));

    StringBuilder sb = new StringBuilder();
    using (StringWriter sw = new StringWriter(sb))
    {
        using (HtmlTextWriter tw = new HtmlTextWriter(sw))
        {
            viewPage.RenderControl(tw);
        }
    }

    return sb.ToString();
}

用法：

string ret = RenderPartialToString("~/Views/MyController/MyPartial.ascx", model);

Answer 3

DaveDev 的答案对我来说效果很好，但是当部分视图调用另一个部分视图时，我得到“值不能为空。参数名称：视图”

搜索周围我做了一个变体 以下 似乎效果很好。

 public static string RenderPartialToString(string viewName, object model, ControllerContext ControllerContext)
    {
        if (string.IsNullOrEmpty(viewName))
            viewName = ControllerContext.RouteData.GetRequiredString("action");
        ViewDataDictionary ViewData = new ViewDataDictionary();
        TempDataDictionary TempData = new TempDataDictionary();
        ViewData.Model = model;

        using (StringWriter sw = new StringWriter())
        {
            ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
            ViewContext viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
            viewResult.View.Render(viewContext, sw);

            return sw.GetStringBuilder().ToString();
        }

    }

用法：

String result = MVCHelpers.RenderPartialToString("PartialViewHere", Model, ControllerContext)

Answer 4

您可以创建将视图呈现为字符串的扩展。

public static class RenderPartialToStringExtensions
{
    /// <summary>
    /// render PartialView and return string
    /// </summary>
    /// <param name="context"></param>
    /// <param name="partialViewName"></param>
    /// <param name="model"></param>
    /// <returns></returns>
    public static string RenderPartialToString(this ControllerContext context, string partialViewName, object model)
    {
        return RenderPartialToStringMethod(context, partialViewName, model);
    }

    /// <summary>
    /// render PartialView and return string
    /// </summary>
    /// <param name="context"></param>
    /// <param name="partialViewName"></param>
    /// <param name="viewData"></param>
    /// <param name="tempData"></param>
    /// <returns></returns>
    public static string RenderPartialToString(ControllerContext context, string partialViewName, ViewDataDictionary viewData, TempDataDictionary tempData)
    {
        return RenderPartialToStringMethod(context, partialViewName, viewData, tempData);
    }

    public static string RenderPartialToStringMethod(ControllerContext context, string partialViewName, ViewDataDictionary viewData, TempDataDictionary tempData)
    {
        ViewEngineResult result = ViewEngines.Engines.FindPartialView(context, partialViewName);

        if (result.View != null)
        {
            StringBuilder sb = new StringBuilder();
            using (StringWriter sw = new StringWriter(sb))
            {
                using (HtmlTextWriter output = new HtmlTextWriter(sw))
                {
                    ViewContext viewContext = new ViewContext(context, result.View, viewData, tempData, output);
                    result.View.Render(viewContext, output);
                }
            }

            return sb.ToString();
        }
        return String.Empty;
    }

    public static string RenderPartialToStringMethod(ControllerContext context, string partialViewName, object model)
    {
        ViewDataDictionary viewData = new ViewDataDictionary(model);
        TempDataDictionary tempData = new TempDataDictionary();
        return RenderPartialToStringMethod(context, partialViewName, viewData, tempData);
    }
}

然后在行动中使用它

[HttpPost]
public ActionResult GetTreeUnit(string id)
{
    int _id = id.ExtractID();
    string render = ControllerContext.RenderPartialToString("SomeView");
    return Json(new { data = render });
}

Answer 5

完美运行（仅需要查看名称）

* 对于参数，您可以使用模型

* 也可以从视图调用

此视图端或调用端

BuyOnlineCartMaster ToInvoice1 = new BuyOnlineCartMaster(); // for passing parameters
ToInvoice1.CartID = 1;

string HtmlString = RenderPartialViewToString("PartialInvoiceCustomer", ToInvoice1);

函数生成 HTML

public class BuyOnlineCartMaster
{
        public int CartID { get; set; }
}

 public static string RenderPartialViewToString(string viewName, object model)
 {    
     using (var sw = new StringWriter())
            {
                BuyOnlineController controller = new BuyOnlineController(); // instance of the required controller (you can pass this as a argument if needed)

                // Create an MVC Controller Context
                var wrapper = new HttpContextWrapper(System.Web.HttpContext.Current);

                RouteData routeData = new RouteData();

                routeData.Values.Add("controller", controller.GetType().Name
                                                            .ToLower()
                                                            .Replace("controller", ""));

                controller.ControllerContext = new ControllerContext(wrapper, routeData, controller);

                controller.ViewData.Model = model;

                var viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName);

                var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
                viewResult.View.Render(viewContext, sw);

                return sw.ToString();
            }
   }

部分视图页面

@{ 
    var ModelContents = (Common.BuyOnlineCartMaster)ViewData.Model;


}

Your cart id : @(ModelContents.CartID)

Answer 6

您可以使用以下方法开箱即用：

var partial = new HtmlString(Html.Partial("_myPartial", Model).ToString());

Answer 7

Dave，

同一主题的变体（mvc v1.0）：

        protected static string RenderPartialToString(Controller controller, string partialName, object model)
    {
        var vd = new ViewDataDictionary(controller.ViewData);
        var vp = new ViewPage
        {
            ViewData = vd,
            ViewContext = new ViewContext(),
            Url = new UrlHelper(controller.ControllerContext.RequestContext)
        };

        ViewEngineResult result = ViewEngines
                                  .Engines
                                  .FindPartialView(controller.ControllerContext, partialName);

        if (result.View == null)
        {
            throw new InvalidOperationException(
            string.Format("The partial view '{0}' could not be found", partialName));
        }
        var partialPath = ((WebFormView)result.View).ViewPath;

        vp.ViewData.Model = model;

        Control control = vp.LoadControl(partialPath);
        vp.Controls.Add(control);

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                vp.RenderControl(tw);
            }
        }
        return sb.ToString();
    }

在控制器中的用法：

        public string GetLocationHighlites()
    {
        IBlockData model = WebPagesMapper.GetLocationHighlites();
        // **this** being the controoler instance
        // LocationPartial.ascx can be defined in shared or in view folder
        return RenderPartialToString(**this**,"LocationPartial", model);
    }

Answer 8

public virtual string RenderPartialViewToString(string viewName, object viewmodel)
        {
            if (string.IsNullOrEmpty(viewName))
            {
                viewName = this.ControllerContext.RouteData.GetRequiredString("action");
            }

            ViewData.Model = viewmodel;

            using (var sw = new StringWriter())
            {
                ViewEngineResult viewResult = System.Web.Mvc.ViewEngines.Engines.FindPartialView(this.ControllerContext, viewName);
                var viewContext = new ViewContext(this.ControllerContext, viewResult.View, this.ViewData, this.TempData, sw);
                viewResult.View.Render(viewContext, sw);
                viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);

                return sw.GetStringBuilder().ToString();
            }
        }

Answer 9

老帖子，但我认为你让这件事变得太困难了。

为什么不 return PartialView("", model); 将返回您想要的字符串。

只需将 Get/Post 方法设置为 IActionResult 作为 JsonResult、PartialResult 以及其他继承自 ActionResult 的方法，您就可以发送回任何内容，包括 JsonResult阿贾克斯

  [HttpPost]
  public IActionResult CheckForContent(string id, string type){
    try{
       
       if(type = "something"){
          return Json(new {
             success = true,
             myProp = "this prop"       
          });
       } else {
          MyViewModel model = new MyViewModel();
          model.Content = _service.GetContent(new GetContentRequest(){ id = id }
          return PartialView("<my partial>", model);
    } catch(Exception ex){
       _logger.LogError(ex.Message);
       return Json(new { success = false }
    }
  }

：

   $.ajax({
      url: '/CheckForContent',
      type: 'POST',
      cache: false,
      contentType: false,
      processData: false,
      success: function (result) {
         if(!result && !result.success){
            console.log("Failed to load");
         } else if(result && result.success){
            $('#MyProp').val(result.myProp);
         } else {
            $('#MyContainer').html(result);
         }
      },
   });

Answer 10

使用 ASP.NET Core 6.0，现有的答案都不适合我，所以我推出了自己的答案。

async Task<string> getPartialViewHtml(string viewName)
{
    var builder = new StringBuilder();
    var writer  = new StringWriter(builder);
    var content = await Html.PartialAsync(viewName);

    content.WriteTo(writer, HtmlEncoder.Default);

    var output = builder.ToString();

    return output;
}

示例用法如下：

var viewHtml = await getPartialViewHtml("PartialViewNameGoesHere");