为什么委托声明前面没有*？
我只是注意到委托声明前面没有 * ...
我做了这样的事情：
@protocol NavBarHiddenDelegate;
@interface AsyncImageView : UIView {
NSURLConnection* connection;
NSMutableData* data;
UIActivityIndicatorView *indicator;
id <NavBarHiddenDelegate> delegate;
}
@property (nonatomic, assign) id <NavBarHiddenDelegate> delegate;
- (id)initWithUrl:(NSString*)url;
@end
@protocol NavBarHiddenDelegate
- (void)hideNavBar;
@end
它工作得很好，但因为我习惯于在我声明的对象前面总是有一个 * ，为什么不呢？ ？！？
谢谢你，
戈泰。
I just noticed there is no * in front of the declaration for a delegate ...
I did something like this :
@protocol NavBarHiddenDelegate;
@interface AsyncImageView : UIView {
NSURLConnection* connection;
NSMutableData* data;
UIActivityIndicatorView *indicator;
id <NavBarHiddenDelegate> delegate;
}
@property (nonatomic, assign) id <NavBarHiddenDelegate> delegate;
- (id)initWithUrl:(NSString*)url;
@end
@protocol NavBarHiddenDelegate
- (void)hideNavBar;
@end
It works perfectly well but as I am used to always but a * in front of objects I declare, why not for this one ?!?
Thank you,
Gotye.
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这与代表无关。
由于历史原因，
id类型有所不同；将其视为任何对象*。每当你写id时，就没有*。如果所有 Objective-C 对象都有一个根类
Object，那么您可以想象typedef Object * id;— 但没有，所以id是不同的（好吧，实际上，如果我没记错的话，它被定义为类似于 struct objc_object * 的东西，但你不应该担心该实现细节与尊重-等级）。This has nothing to do with delegates.
The type
idis different, for historical reasons; think of it asany-object *. Whenever you writeid, there is no*.If there were a single root class
Objectfor all Objective-C objects then you could imagine thattypedef Object * id;— but there isn't, soidis different (well, actually, it's defined as something likestruct objc_object *if I recall correctly, but you shouldn't worry about that implementation-detail-with-respect-to-this-level).因为
id已经有了它隐含的*。如果您忽略协议限制，则显然
不需要
*。顺便说一句，如果协议放在 ObjC 类型上，那么您需要*，例如Because
idalready has its implicit*. If you ignore the protocol restriction thenbecomes
which obviously doesn't need a
*. BTW, if the protocol is put on an ObjC type then you need the*, e.g.