使用 xml.dom.minidom 更新元素值

发布于 2024-08-25 22:08:14 字数 1693 浏览 5 评论 0原文

我有一个 XML 结构,看起来类似于:

<Store>
   <foo>
      <book>
        <isbn>123456</isbn>
      </book>
      <title>XYZ</title>
      <checkout>no</checkout>
   </foo>

   <bar>
      <book>
        <isbn>7890</isbn>
      </book>
      <title>XYZ2</title>
      <checkout>yes</checkout>
   </bar>
</Store>

仅使用 xml.dom.minidom(限制) 我想

1)遍历 XML 文件

2)搜索/获取特定元素,具体取决于其父元素

示例:author1 的 checkout 元素,isbn 为author2

3)更改/设置该元素的值

4)将新的XML 结构写入文件

有人可以帮忙吗?

谢谢你!

更新

这就是我到目前为止所做的

import xml.dom.minidom
checkout = "yes"

def getLoneChild(node, tagname):

  assert ((node is not None) and (tagname is not None))
  elem = node.getElementsByTagName(tagname)
  if ((elem is None) or (len(elem) != 1)):
    return None
  return elem

def getLoneLeaf(node, tagname):

  assert ((node is not None) and (tagname is not None))
  elem = node.getElementsByTagName(tagname)
  if ((elem is None) or (len(elem) != 1)):
    return None
  leaf = elem[0].firstChild
  if (leaf is None):
    return None
  return leaf.data


def setcheckout(node, tagname):

  assert ((node is not None) and (tagname is not None))
  child = getLoneChild(node, 'foo')
  Check = getLoneLeaf(child[0],'checkout')
  Check = tagname
  return Check

doc = xml.dom.minidom.parse('test.xml') 
root = doc.getElementsByTagName('Store')[0]
output = setcheckout(root, checkout)

tmp_config = '/tmp/tmp_config.xml' 
fw = open(tmp_config, 'w')
fw.write(doc.toxml())
fw.close()

I have an XML structure which looks similar to:

<Store>
   <foo>
      <book>
        <isbn>123456</isbn>
      </book>
      <title>XYZ</title>
      <checkout>no</checkout>
   </foo>

   <bar>
      <book>
        <isbn>7890</isbn>
      </book>
      <title>XYZ2</title>
      <checkout>yes</checkout>
   </bar>
</Store>

Using xml.dom.minidom only (restrictions) i would like to

1)traverse through the XML file

2)Search/Get for particular element, depending on its parent

Example: checkout element for author1, isbn for author2

3)Change/Set that element's value

4)Write the new XML structure to a file

Can anyone help here?

Thank you!

UPDATE:

This is what i have done till now

import xml.dom.minidom
checkout = "yes"

def getLoneChild(node, tagname):

  assert ((node is not None) and (tagname is not None))
  elem = node.getElementsByTagName(tagname)
  if ((elem is None) or (len(elem) != 1)):
    return None
  return elem

def getLoneLeaf(node, tagname):

  assert ((node is not None) and (tagname is not None))
  elem = node.getElementsByTagName(tagname)
  if ((elem is None) or (len(elem) != 1)):
    return None
  leaf = elem[0].firstChild
  if (leaf is None):
    return None
  return leaf.data


def setcheckout(node, tagname):

  assert ((node is not None) and (tagname is not None))
  child = getLoneChild(node, 'foo')
  Check = getLoneLeaf(child[0],'checkout')
  Check = tagname
  return Check

doc = xml.dom.minidom.parse('test.xml') 
root = doc.getElementsByTagName('Store')[0]
output = setcheckout(root, checkout)

tmp_config = '/tmp/tmp_config.xml' 
fw = open(tmp_config, 'w')
fw.write(doc.toxml())
fw.close()

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评论(1

失与倦" 2024-09-01 22:08:14

我不完全确定你所说的“结账”是什么意思。该脚本将找到该元素并更改该元素的值。也许您可以根据您的特定需求进行调整。

import xml.dom.minidom as DOM

# find the author as a child of the "Store"
def getAuthor(parent, author):
  # by looking at the children
  for child in [child for child  in parent.childNodes 
                if child.nodeType != DOM.Element.TEXT_NODE]:
    if child.tagName == author:
      return child
  return None

def alterElement(parent, attribute, newValue):
  found = False;
  # look through the child elements, skipping Text_Nodes 
  #(in your example these hold the "values"
  for child in [child for child  in parent.childNodes 
                if child.nodeType != DOM.Element.TEXT_NODE]:

    # if the child element tagName matches target element name
    if child.tagName == attribute:
      # alter the data, i.e. the Text_Node value, 
      # which is the firstChild of the "isbn" element
      child.firstChild.data = newValue
      return True

    else:
      # otherwise look at all the children of this node.
      found = alterElement(child, attribute, newValue)

    if found:
      break 

  # return found status
  return found

doc = DOM.parse("test.xml")
# This assumes that there is only one "Store" in the file
root = doc.getElementsByTagName("Store")[0]

# find the author
# this assumes that there are no duplicate author names in the file
author = getAuthor(root, "foo")
if not author:
  print "Author not found!"
else:
  # alter an element
  if not alterElement(author, "isbn", "987654321"):
    print "isbn not found"
  else:
    # output the xml
    tmp_config = '/tmp/tmp_config.xml'
    f = open(tmp_config, 'w')
    doc.writexml( f )
    f.close()

总体思路是,将作者的姓名与“Store”元素的子元素的 tagName 进行匹配,然后递归遍历作者的子元素,查找与目标元素 tagName 的匹配项。此解决方案中做出了很多假设,但它可能会帮助您入门。尝试在不使用递归的情况下处理像 XML 这样的分层结构是很痛苦的。


回想起来,“alterElement”函数中有一个错误。我已经解决了这个问题(注意“找到的”变量”)

I'm not entirely sure what you mean by "checkout". This script will find the element and alter the value of that element. Perhaps you can adapt it to your specific needs.

import xml.dom.minidom as DOM

# find the author as a child of the "Store"
def getAuthor(parent, author):
  # by looking at the children
  for child in [child for child  in parent.childNodes 
                if child.nodeType != DOM.Element.TEXT_NODE]:
    if child.tagName == author:
      return child
  return None

def alterElement(parent, attribute, newValue):
  found = False;
  # look through the child elements, skipping Text_Nodes 
  #(in your example these hold the "values"
  for child in [child for child  in parent.childNodes 
                if child.nodeType != DOM.Element.TEXT_NODE]:

    # if the child element tagName matches target element name
    if child.tagName == attribute:
      # alter the data, i.e. the Text_Node value, 
      # which is the firstChild of the "isbn" element
      child.firstChild.data = newValue
      return True

    else:
      # otherwise look at all the children of this node.
      found = alterElement(child, attribute, newValue)

    if found:
      break 

  # return found status
  return found

doc = DOM.parse("test.xml")
# This assumes that there is only one "Store" in the file
root = doc.getElementsByTagName("Store")[0]

# find the author
# this assumes that there are no duplicate author names in the file
author = getAuthor(root, "foo")
if not author:
  print "Author not found!"
else:
  # alter an element
  if not alterElement(author, "isbn", "987654321"):
    print "isbn not found"
  else:
    # output the xml
    tmp_config = '/tmp/tmp_config.xml'
    f = open(tmp_config, 'w')
    doc.writexml( f )
    f.close()

The general idea is that you match the name of the author against the tagNames of the children of the "Store" element, then recurse through the children of the author, looking for a match against a target element tagName. There are a lot of assumptions made in this solution, but it may get you started. It's painful to try and deal with hierarchical structures like XML without using recursion.


In retrospect there was an error in the "alterElement" function. I've fixed this (note the "found" variable")

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