了解 DirectoryInfo.Exists 上的布尔值
var fileOpen = new OpenFileDialog(); var clickedOk = fileOpen.ShowDialog(); if (!((bool) clickedOk)) 返回；
var path = fileOpen.FileName;
var diPath = new DirectoryInfo(path);
var fiPath = new FileInfo(path);
Debug.WriteLine(diPath.Exists);
我只是想知道为什么 diPath.Exists 在这种情况下是假的？既然用户选择了文件，那么该目录就必须存在！？确实如此...
我已经使用 Directory.Exists(fiPath.DirectoryName) 进行了解决，但似乎很奇怪，上面的方法不起作用，并且需要其他 var 有点令人恼火检查我知道的东西是否存在，并且应该能够使用 diPath。这是怎么回事？
另外，关于一个相关问题，假设我有一个目录 C:\random\spot\here 的目录信息，为什么没有方法获取该字符串“C:\random\spot\here”，似乎我只能获取 Parent “spot” ”或名称“此处”。也许我错过了什么。
谢谢，
var fileOpen = new OpenFileDialog();
var clickedOk = fileOpen.ShowDialog();
if (!((bool) clickedOk)) return;
var path = fileOpen.FileName;
var diPath = new DirectoryInfo(path);
var fiPath = new FileInfo(path);
Debug.WriteLine(diPath.Exists);
I am just wondering why diPath.Exists is false in this case? Since the user has selected a file, the directory must exist!? and it does...
I have used a work around by using Directory.Exists(fiPath.DirectoryName) but it seems strange that the above isn't working, and slightly irritating to need that other var just to check something that I know is there exists, and should just be able to use the diPath. What's the deal?
Also on a related matter, say I have a directoryinfo for a directory C:\random\spot\here why is there no method to obtain that string "C:\random\spot\here" it seems I can only get Parent "spot" or Name "here". Maybe I missed something.
Thanks,
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有一个名为
path的文件，但没有名为path的目录。可能就是你想要的。
There is a file called
pathbut there is not directory called path.is probably what you want.
您在“路径”中包含文件名，因此路径将是叶节点（即文件）而不是目录（分支节点）。 Windows 文件/路径处理对于这类事情来说是非常字面的。
如前所述，如果使用路径，您可能需要使用 DirectoryInfo 或 Path.GetDirectoryName()。
Your including the filename in the "path", and as such the path will be a leaf node (i.e. file) and not a directory (branch node). Windows file/path handling is quite literal about those kind of things.
As mentioned previously DirectoryInfo or Path.GetDirectoryName() is probably what you want to use if working with paths.