当使用 include() 包含相对路径时，PHP 会检查哪些目录？

发布于 2024-08-24 19:42:09 字数 910 浏览 2 评论 0原文

很奇怪，有人总结过结论吗？

有时它也会检查包含文件的目录。

但有时不是。

D:\test\1.php

<?php

include('sub\2.php');

D:\test\2.php

<?php

include('3.php');

其中 3.php 与 2.php 位于同一目录中。

上面的方法是有效的，但是为什么呢？当前目录应该是D:\test，但它仍然可以找到3.php，它在D:\test\sub

<强>更多故事（最终）

大约一年前，我遇到了这个问题，然后我最终用如下的硬编码修复了它：

Common.php：

if (file_exists("../../../Common/PHP/Config.inc"))
    include('../../../Common/PHP/Config.inc');

if (file_exists("../../Common/PHP/Config.inc"))
    include('../../Common/PHP/Config.inc');

if (file_exists("../Common/PHP/Config.inc"))
    include('../Common/PHP/Config.inc');

if (file_exists("Common/PHP/Config.inc"))
    include('Common/PHP/Config.inc');

其中Config。 inc 与 Common.php 位于同一目录中

原文

It's very odd,has anyone ever sum up with a conclusion yet?

Sometimes it checks the directory of the included file,too.

But sometimes not.

D:\test\1.php

<?php

include('sub\2.php');

D:\test\2.php

<?php

include('3.php');

Where 3.php is in the same dir as 2.php.

The above works,but why?The current directory should be D:\test,but it can still find 3.php,which is in D:\test\sub

More story(final)

About a year ago I met this problem,and then I ended up fixed it with the hardcoding like below:

Common.php:

if (file_exists("../../../Common/PHP/Config.inc"))
    include('../../../Common/PHP/Config.inc');

if (file_exists("../../Common/PHP/Config.inc"))
    include('../../Common/PHP/Config.inc');

if (file_exists("../Common/PHP/Config.inc"))
    include('../Common/PHP/Config.inc');

if (file_exists("Common/PHP/Config.inc"))
    include('Common/PHP/Config.inc');

Where Config.inc is in the same directory as Common.php

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我为君王 2024-08-31 19:42:09

如果您查看 main/fopen_wrappers.c 中 php 的源代码，您会发现

/* check in calling scripts' current working directory as a fall back case
     */
    if (zend_is_executing(TSRMLS_C)) {
        char *exec_fname = zend_get_executed_filename(TSRMLS_C);
        int exec_fname_length = strlen(exec_fname);

        while ((--exec_fname_length >= 0) && !IS_SLASH(exec_fname[exec_fname_length]));
        if (exec_fname && exec_fname[0] != '[' &&
            exec_fname_length > 0 &&
            exec_fname_length + 1 + filename_length + 1 < MAXPATHLEN) {
            memcpy(trypath, exec_fname, exec_fname_length + 1);
            memcpy(trypath+exec_fname_length + 1, filename, filename_length+1);
            actual_path = trypath;

这似乎是无条件执行的，因此始终会在与包含/文件打开脚本可访问的路径相同的路径中创建一个文件... include_path 中指定的所有可能性之后的最后一个选择。并且仅当您未在 include() 中定义相对或绝对路径时。

If you take a look at the source code for php in main/fopen_wrappers.c you will find

/* check in calling scripts' current working directory as a fall back case
     */
    if (zend_is_executing(TSRMLS_C)) {
        char *exec_fname = zend_get_executed_filename(TSRMLS_C);
        int exec_fname_length = strlen(exec_fname);

        while ((--exec_fname_length >= 0) && !IS_SLASH(exec_fname[exec_fname_length]));
        if (exec_fname && exec_fname[0] != '[' &&
            exec_fname_length > 0 &&
            exec_fname_length + 1 + filename_length + 1 < MAXPATHLEN) {
            memcpy(trypath, exec_fname, exec_fname_length + 1);
            memcpy(trypath+exec_fname_length + 1, filename, filename_length+1);
            actual_path = trypath;

This seems to be executed unconditionally and therefore will always make a file in the same path as the including/file-opening script accessible ...as the last choice after all possibilities specified in include_path. And only if you do not define a relative or absolute path in the include().

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