PHP preg_replace_callback 的正则表达式

发布于 2024-08-24 06:34:54 字数 835 浏览 8 评论 0原文

正则表达式不是我的菜。 :(

我有一个可能包含多个子字符串的字符串，例如：

[var1="111" var2="222" var3="222" var4="444"]

我基本上需要将每个出现的地方替换为获取每个变量的函数的结果。

$string = '[var1="111" var2="222" var3="333" var4="444"]';    
$regex = 'var1="(.*)" var2="(.*)" var3="(.*)" var4="(.*)"';

function doit($matches){
    return "<strong>".implode(", ", $matches) ."</strong>";
}

echo preg_replace_callback($regex,'doit',$string);

我期望 111, 222, 333, 444.

但我没有感受到任何帮助！

编辑：一些澄清..

我只是为了这个问题而简化

“vars”实际上并没有。是称为“var1”，“var2”更像 [recID =“22”模板=“theName” option="some value", type="list"]
回调会更多复杂然后我简单内爆...我会使用“id”和连接到数据库，获取记录并将它们插入到模板...因此需要回电...
匹配的值可能几乎任何东西，而不仅仅是数字。

原文

Regular expressions is just not my thing. :(

I have a string that may contain multiple sub strings such as:

[var1="111" var2="222" var3="222" var4="444"]

I basically need to replace each occurrence with the results of a function that gets each variable.

$string = '[var1="111" var2="222" var3="333" var4="444"]';    
$regex = 'var1="(.*)" var2="(.*)" var3="(.*)" var4="(.*)"';

function doit($matches){
    return "<strong>".implode(", ", $matches) ."</strong>";
}

echo preg_replace_callback($regex,'doit',$string);

I’m expecting 111, 222, 333, 444.

But I’m not feeling the love. Any help would be appreciated!

Edit: some clarification..

I was simplifying for the sake of the question.

the "vars" will not really be
called "var1", "var2" more like
[recID="22" template="theName"
option="some value", type="list"]
the call back would be more
complicated then my simple
implode... I would use "id" and
connect to a database, get the
records and insert them into the
template... Hence the need for the
call back...
matched values could be almost
anything, not just numbers.

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赠意 2024-08-31 06:34:54

我会分两步完成：

获取标签
获取每个标签的属性

这是一个示例：

function doit($match) {
    $parts = preg_split('/(\w+="[^"]*")/', $match[1], -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);
    foreach ($parts as $part) {
        if (trim($part) !== "") {
            if (!preg_match('/^(\w+)="([^"]*)"$/', $part, $match)) {
                // syntax error
            } else {
                var_dump($match);
            }
        }
    }
}

$str = '[var1="111" var2="222" var3="333" var4="444"]';
$re = '/\[((?:[^"[\]]+|"[^"]*")*)]/';
preg_replace_callback($re, 'doit', $str);

通过这个，您甚至可以检测语法错误。

这不是一个完美的解决方案，因为逐字符读取输入并根据它们所在的上下文确定标记会更有效。

I would do it in two step:

Get the tags
Get the attributes for each tag

Here’s an example:

function doit($match) {
    $parts = preg_split('/(\w+="[^"]*")/', $match[1], -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);
    foreach ($parts as $part) {
        if (trim($part) !== "") {
            if (!preg_match('/^(\w+)="([^"]*)"$/', $part, $match)) {
                // syntax error
            } else {
                var_dump($match);
            }
        }
    }
}

$str = '[var1="111" var2="222" var3="333" var4="444"]';
$re = '/\[((?:[^"[\]]+|"[^"]*")*)]/';
preg_replace_callback($re, 'doit', $str);

With this you can even detect syntax errors.

It’s not a perfect solution as it would be more efficient to read the input character by character and determine the tokens depending on the contexts they are found in.

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不气馁 2024-08-31 06:34:54

另一个答案可能是更好的解决方案，但以下是如何使用 preg_replace_callback 来做到这一点：

$string = '[var1="111" var2="222" var3="333" var4="444"]';

// Note: regular expressions need to start and end with /
$regex = '/var1="(.*)" var2="(.*)" var3="(.*)" var4="(.*)"/';

function doit($matches){
    // The first element of matches is the complete
    // match, shift is here just to get rid of it
    // (probably a better way to do this)
    array_shift($matches);
    return "<strong>".implode(", ", $matches) ."</strong>";
}
echo preg_replace_callback($regex,'doit',$string);

The other answer may be a better solution, but here is how you could do it with preg_replace_callback:

$string = '[var1="111" var2="222" var3="333" var4="444"]';

// Note: regular expressions need to start and end with /
$regex = '/var1="(.*)" var2="(.*)" var3="(.*)" var4="(.*)"/';

function doit($matches){
    // The first element of matches is the complete
    // match, shift is here just to get rid of it
    // (probably a better way to do this)
    array_shift($matches);
    return "<strong>".implode(", ", $matches) ."</strong>";
}
echo preg_replace_callback($regex,'doit',$string);

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