在没有map.onMouseMove的情况下在GoogleMaps中获取光标下的纬度和经度

发布于 2024-08-23 10:55:40 字数 721 浏览 3 评论 0 原文

我有 GoogleMaps 对象。我还有 GLatLng 格式的西南点和东北点。另外，我的对象上有 (x,y) 光标。我想知道光标下的GLatLng而不使用map.onMouseMove（仅使用DOM-onMouveMove）。我尝试编写 JavaScript 代码：

        var w = map.getSize().width;
        var h = map.getSize().height;
        var left = map.getBounds().getSouthWest().lat();
        var right = map.getBounds().getNorthEast().lat();
        var top = map.getBounds().getSouthWest().lng();
        var bottom = map.getBounds().getNorthEast().lng();
        var x = e.pageX - map_canvas.offsetLeft;
        var y = e.pageY - map_canvas.offsetTop;
        var lng = top + (bottom - top) * x * 1.0 / w;
        var lat = left + (right - left) * (h - y) * 1.0 / h;

但这样我的准确性不够。屏幕地理坐标的正常变换公式是什么？

原文

I have GoogleMaps-object. Also I have SouthWest and NorthEast point in GLatLng-format. Also I have (x,y) of cursor over my object. I want know GLatLng under cursor without use map.onMouseMove (only use DOM-onMouveMove). I try write JavaScript-code:

        var w = map.getSize().width;
        var h = map.getSize().height;
        var left = map.getBounds().getSouthWest().lat();
        var right = map.getBounds().getNorthEast().lat();
        var top = map.getBounds().getSouthWest().lng();
        var bottom = map.getBounds().getNorthEast().lng();
        var x = e.pageX - map_canvas.offsetLeft;
        var y = e.pageY - map_canvas.offsetTop;
        var lng = top + (bottom - top) * x * 1.0 / w;
        var lat = left + (right - left) * (h - y) * 1.0 / h;

But in this way I do not have enough accuracy. What is the normal transformation formulas in the geographic coordinates of the screen?

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