使用 TRUE 和 FALSE 数组索引 data.frames

发布于 2024-08-23 07:26:45 字数 1184 浏览 6 评论 0原文

我在 R 中索引 data.frames 时遇到一些问题。我是 R 初学者。我有一个名为 ddata.frame,它有 35512 列和 77 行。我有一个名为 rd 的列表,其中包含 35512 个元素。我希望 d 中与 rd 中的项目相对应的所有列都小于 100。这就是我正在做的事情:

# just to prove I'm not crazy
> length(colnames(d))
[1] 35512
> length(rownames(d))
[1] 77
> length(rd)
[1] 35512
# find all the elements of rd less than 100 (+ unnecessary faffing?)
> i <- unlist(rd<100)
> names(i) <- NULL
# try to extract all the elements of d corresponding to rd < 100
> d <- d[,i]
Error in `[.data.frame`(d, , i) : undefined columns selected

我真的不想做unlistnames(i) <- NULL 的东西,但我变得非常偏执。谁能帮忙解释一下这个错误消息到底意味着什么?

如果有帮助,可以使用以下命令创建 rd 变量:

rd = lapply(lapply(d, range), diff)

希望能够告诉我 d 的每列范围的差异。

PS 对于任何能告诉我一个命令来查找 data.frame 的形状而不是查询其行和列名称的长度的人来说,这真是太棒了。

编辑:这是 rd 的样子:

> rd[1:3]
$`10338001`
[1] 7198.886

$`10338003`
[1] 4748.963

$`10338004`
[1] 3173.046

当我完成我的工作后,i 看起来像这样:

> i[7:10]
[1] FALSE FALSE FALSE  TRUE

I'm having some trouble indexing data.frames in R. I'm an R beginner. I have a data.frame called d which has 35512 columns and 77 rows. I have a list called rd which contains 35512 elements. I'd like all the columns of d which correspond to the items in rd less than 100. Here's what I'm doing:

# just to prove I'm not crazy
> length(colnames(d))
[1] 35512
> length(rownames(d))
[1] 77
> length(rd)
[1] 35512
# find all the elements of rd less than 100 (+ unnecessary faffing?)
> i <- unlist(rd<100)
> names(i) <- NULL
# try to extract all the elements of d corresponding to rd < 100
> d <- d[,i]
Error in `[.data.frame`(d, , i) : undefined columns selected

I don't really want to be doing the unlist and names(i) <- NULL stuff but I'm getting seriously paranoid. Can anyone help with what the hell this error message means?

In case it helps, the rd variable is created using the following:

rd = lapply(lapply(d, range), diff)

Which hopefully tells me the difference in the range of each column of d.

P.S. bonus awesomeness for anyone who can tell me a command to find the shape of a data.frame other than querying the length of its row and column names.

Edit: Here's what rd looks like:

> rd[1:3]

I'm having some trouble indexing data.frames in R. I'm an R beginner. I have a data.frame called d which has 35512 columns and 77 rows. I have a list called rd which contains 35512 elements. I'd like all the columns of d which correspond to the items in rd less than 100. Here's what I'm doing:

# just to prove I'm not crazy
> length(colnames(d))
[1] 35512
> length(rownames(d))
[1] 77
> length(rd)
[1] 35512
# find all the elements of rd less than 100 (+ unnecessary faffing?)
> i <- unlist(rd<100)
> names(i) <- NULL
# try to extract all the elements of d corresponding to rd < 100
> d <- d[,i]
Error in `[.data.frame`(d, , i) : undefined columns selected

I don't really want to be doing the unlist and names(i) <- NULL stuff but I'm getting seriously paranoid. Can anyone help with what the hell this error message means?

In case it helps, the rd variable is created using the following:

rd = lapply(lapply(d, range), diff)

Which hopefully tells me the difference in the range of each column of d.

P.S. bonus awesomeness for anyone who can tell me a command to find the shape of a data.frame other than querying the length of its row and column names.

Edit: Here's what rd looks like:

10338001` [1] 7198.886

I'm having some trouble indexing data.frames in R. I'm an R beginner. I have a data.frame called d which has 35512 columns and 77 rows. I have a list called rd which contains 35512 elements. I'd like all the columns of d which correspond to the items in rd less than 100. Here's what I'm doing:

# just to prove I'm not crazy
> length(colnames(d))
[1] 35512
> length(rownames(d))
[1] 77
> length(rd)
[1] 35512
# find all the elements of rd less than 100 (+ unnecessary faffing?)
> i <- unlist(rd<100)
> names(i) <- NULL
# try to extract all the elements of d corresponding to rd < 100
> d <- d[,i]
Error in `[.data.frame`(d, , i) : undefined columns selected

I don't really want to be doing the unlist and names(i) <- NULL stuff but I'm getting seriously paranoid. Can anyone help with what the hell this error message means?

In case it helps, the rd variable is created using the following:

rd = lapply(lapply(d, range), diff)

Which hopefully tells me the difference in the range of each column of d.

P.S. bonus awesomeness for anyone who can tell me a command to find the shape of a data.frame other than querying the length of its row and column names.

Edit: Here's what rd looks like:

10338003` [1] 4748.963

I'm having some trouble indexing data.frames in R. I'm an R beginner. I have a data.frame called d which has 35512 columns and 77 rows. I have a list called rd which contains 35512 elements. I'd like all the columns of d which correspond to the items in rd less than 100. Here's what I'm doing:

# just to prove I'm not crazy
> length(colnames(d))
[1] 35512
> length(rownames(d))
[1] 77
> length(rd)
[1] 35512
# find all the elements of rd less than 100 (+ unnecessary faffing?)
> i <- unlist(rd<100)
> names(i) <- NULL
# try to extract all the elements of d corresponding to rd < 100
> d <- d[,i]
Error in `[.data.frame`(d, , i) : undefined columns selected

I don't really want to be doing the unlist and names(i) <- NULL stuff but I'm getting seriously paranoid. Can anyone help with what the hell this error message means?

In case it helps, the rd variable is created using the following:

rd = lapply(lapply(d, range), diff)

Which hopefully tells me the difference in the range of each column of d.

P.S. bonus awesomeness for anyone who can tell me a command to find the shape of a data.frame other than querying the length of its row and column names.

Edit: Here's what rd looks like:

10338004` [1] 3173.046

and when I've done my faffing, i looks like this:

> i[7:10]
[1] FALSE FALSE FALSE  TRUE

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评论(2

许久 2024-08-30 07:26:45

您尝试过吗:

d[,rd < 100]

这是一个独立的示例:

d <- data.frame(matrix(1:100, ncol=10))
rd <- as.list(1:10)
d[,rd < 5]

要获取数据框的形状,请使用 nrowncol

编辑:

根据您对我的NA问题的回答,听起来您的索引中存在非逻辑值,这些值是由于列表中缺少值而导致的。最好的办法是首先决定如何处理缺失值。然后使用 is.na 函数处理它们(这里我扩展了上面的示例):

rd[[3]] <- NA
d[,rd < 5]
# => Error in `[.data.frame`(d, , rd < 5) : undefined columns selected

为了处理这个问题,我将把 NA 值设置为 0(这意味着相应的列将是包含在最终的 data.frame 中):

rd[is.na(rd)] <- 0
d[,rd < 5]

您需要自己决定如何处理 NA 值。

Have you tried this:

d[,rd < 100]

Here's a self-contained example:

d <- data.frame(matrix(1:100, ncol=10))
rd <- as.list(1:10)
d[,rd < 5]

To get the shape of a dataframe, use nrow and ncol.

Edit:

Based on your response to my NA question, it sounds like you have non-logical values in your index that result from missing values in your list. The best thing to do is to first decide how you want to treat a missing value. Then deal with them using the is.na function (here I extend my example from above):

rd[[3]] <- NA
d[,rd < 5]
# => Error in `[.data.frame`(d, , rd < 5) : undefined columns selected

To deal with this, I will set that NA value to 0 (which means that it the respective column will be included in the final data.frame):

rd[is.na(rd)] <- 0
d[,rd < 5]

You need to decide for yourself what to do with the NA values.

心如狂蝶 2024-08-30 07:26:45

对于额外的 Q,您可以使用“dim”命令获得数据框或矩阵的“形状”。

A = matrix( ceiling(10*runif(40)), nrow=8)
colnames(A) = c("col1", "col2", "col3", "col4", "col5")
df = data.frame(A)
b = ceiling(100*runif(5))

ndx = b < 50          
result = df[,ndx]     # just the columns of df corresponding to b < 50

For the bonus Q, you get "shape" of a data frame or matrix using the "dim" command.

A = matrix( ceiling(10*runif(40)), nrow=8)
colnames(A) = c("col1", "col2", "col3", "col4", "col5")
df = data.frame(A)
b = ceiling(100*runif(5))

ndx = b < 50          
result = df[,ndx]     # just the columns of df corresponding to b < 50
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