using 块是否创建并维护 GC 的引用？
这主要是出于好奇，因为有更好的方法来实现我能想到的这种构造的几乎所有用例（至少在我经常使用的 C# 和其他语言中），但我最近在这里看到了 作用域互斥体一个很酷的概念。
我的问题是，using 语句是否维护对其所作用的对象的引用（即：阻止 GC 运行）？
例如，如果我这样做：
using (new ScopedMutex())
{
// ...
}
ScopedMutex 对象是否会在 using 块结束时保持其存在，或者 GC 是否可以在块中运行并处理它？
This is mostly for curiosity's sake, as there are better ways of implementing almost any use case I can think of for this construct (in C# and other languages I use regularly, at least), but I recently saw on here a scoped mutex which was a cool concept.
My question is, does the using statement maintain a reference (ie: prevent the GC from running on) to the object it's acting on?
For example, if I were to do:
using (new ScopedMutex())
{
// ...
}
would the ScopedMutex object maintain its existence to the end of the using block, or could the GC run and dispose of it mid-block?
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不，GC 不会处置它。对该对象的引用存储在局部变量中（有关详细信息，请参阅此答案）。局部变量被视为 GC 根，并且可以从它访问该对象（
using块需要可以访问该对象才能对其调用Dispose）。No, the GC will not dispose it. A reference to that object is stored in a local variable (see this answer for more info). A local variable is considered a GC root and the object will be reachable from it (it needs to be reachable for the
usingblock to be able to callDisposeon it).C# 编译器将隐式为您创建一个变量。 using 语句在编译时实际上会转换为如下内容（您可以使用 Redgate Reflector< /a> 亲自查看确切的代码，顺便说一句）：
The C# compiler will implicitly create a variable for you. The using statement would actually be transformed into something like the following when compiled (you can use Redgate Reflector to see the exact code for yourself, btw):
它不会将其处置在区块中间。
It will not dispose it in mid-block.