php 类扩展 - 具有相同名称的属性/方法可以吗？

发布于 2024-08-22 09:15:03 字数 487 浏览 4 评论 0原文

例如，如果您有一个名为“User”的类和另一个扩展“User”的名为“Admin”的类，并且您希望 Admin 继承 User 的所有属性和方法，但 __construct 方法除外。

class User {
private $name;

function __construct($name) {
$this->name = $name;
}
}

？

class Admin extends User {
private $authorization;

function __construct($name,$authorization) {
$this->name = $name;
$this->authorization = $authorization;
}
}

这是正确的吗管理员是否会覆盖用户的构造方法？如果扩展类具有相同的方法名称，我认为它是无效的。我完全错过了课程扩展的意义吗？

原文

If you have a class named "User" and another class named "Admin" that extends "User", and you want Admin to inherit all attributes,methods from User, except for the __construct method, for example.

class User {
private $name;

function __construct($name) {
$this->name = $name;
}
}

and

class Admin extends User {
private $authorization;

function __construct($name,$authorization) {
$this->name = $name;
$this->authorization = $authorization;
}
}

Is this correct? Does Admin override User's construct method? If the extending class has the same method name I suppose it's invalid.
Am I totally missing the point of class extension?

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蘸点软妹酱 2024-08-29 09:15:03

它并不是无效的。类继承的一个方面是，您可以重写方法并提供另一种实现。

但就你而言，我会这样做，

class Admin extends User {
    private $authorization;

    function __construct($name,$authorization) {
        parent::__construct($name);
        $this->authorization = $authorization;
    }
}

因为你已经在父类中实现了“名称分配”。这是一种更清洁的方法。

It is not invalid. One aspect of class inheritance is, that you can override methods and provide another implementation.

But in your case, I would do

class Admin extends User {
    private $authorization;

    function __construct($name,$authorization) {
        parent::__construct($name);
        $this->authorization = $authorization;
    }
}

as you already implement the "name assignment" in the parent class. It is a cleaner approach.

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