如何为抽象类的子类声明默认构造函数？
以下内容在 Java 中对我不起作用。 Eclipse 抱怨没有这样的构造函数。我已将构造函数添加到子类中以解决它，但是还有其他方法可以完成我想要做的事情吗？
public abstract class Foo {
String mText;
public Foo(String text) {
mText = text;
}
}
public class Bar extends Foo {
}
Foo foo = new Foo("foo");
The following doesn't work for me in Java. Eclipse complains that there is no such constructor. I've added the constructor to the sub-class to get around it, but is there another way to do what I'm trying to do?
public abstract class Foo {
String mText;
public Foo(String text) {
mText = text;
}
}
public class Bar extends Foo {
}
Foo foo = new Foo("foo");
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评论（2）
您无法实例化
Foo因为它是抽象的。相反，
Bar需要一个调用super(String)构造函数的构造函数。例如，
这里我将
text字符串传递给超级构造函数。但你可以这样做（例如）：super()构造必须是子类构造函数中的第一个语句。You can't instantiate
Foosince it's abstract.Instead,
Barneeds a constructor which calls thesuper(String)constructor.e.g.
Here I'm passing the
textstring through to the super constructor. But you could do (for instance):The
super()construct needs to be the first statement in the subclass constructor.您无法从抽象类实例化，这就是您在这里尝试的。你确定你不是说：
？？？
You can't instantiate from an abstract class and that's what you are trying here. Are you sure that you didn't mean:
???