jBCrypt 0.3 C# 端口 (BCrypt.net)

发布于 2024-08-20 20:37:57 字数 1461 浏览 4 评论 0原文

在研究了原始 jBCrypt v0.1 C# 端口中的错误后: BCrypt.net (相关问题)。我决定将新的 jBCrypt 代码与旧的 C# 端口进行比较,以查找差异和潜在问题,例如相关问题的错误。

这是我发现的:

// original java (jBCrypt v0.3):
private static int streamtoword(byte data[], int offp[]) {
        int i;
        int word = 0;
        int off = offp[0];

        for (i = 0; i < 4; i++) {
            word = (word << 8) | (data[off] & 0xff);
            off = (off + 1) % data.length;
        }

        offp[0] = off;
        return word;
}


// port to C# :
private static uint StreamToWord(byte[] data, ref int offset)
{

    uint word = 0;

    for (int i = 0; i < 4; i++)
    {
        // note the difference with the omission of "& 0xff"
        word = (word << 8) | data[offset];
        offset = (offset + 1) % data.Length;
    }

    return word;
}

如果先验不正确,以下内容会修复它吗?

private static uint StreamToWord(byte[] data, ref int[] offsetp)
{

    uint word = 0;
    int offset = offsetp[0];
    for (int i = 0; i < 4; i++)
    {
        word = (word << 8) | (uint)(data[offset] & 0xff);
        offset = (offset + 1) % data.Length;
    }

    offsetp[0] = offset;

    return word;
}

After looking into a bug in the original jBCrypt v0.1 C# port: BCrypt.net (Related Question). I decided to compare the new jBCrypt code against the old C# port to look for discrepancies and potential issues like the related question's bug.

Here is what I've found:

// original java (jBCrypt v0.3):
private static int streamtoword(byte data[], int offp[]) {
        int i;
        int word = 0;
        int off = offp[0];

        for (i = 0; i < 4; i++) {
            word = (word << 8) | (data[off] & 0xff);
            off = (off + 1) % data.length;
        }

        offp[0] = off;
        return word;
}


// port to C# :
private static uint StreamToWord(byte[] data, ref int offset)
{

    uint word = 0;

    for (int i = 0; i < 4; i++)
    {
        // note the difference with the omission of "& 0xff"
        word = (word << 8) | data[offset];
        offset = (offset + 1) % data.Length;
    }

    return word;
}

if the prior is incorrect would the following fix it?

private static uint StreamToWord(byte[] data, ref int[] offsetp)
{

    uint word = 0;
    int offset = offsetp[0];
    for (int i = 0; i < 4; i++)
    {
        word = (word << 8) | (uint)(data[offset] & 0xff);
        offset = (offset + 1) % data.Length;
    }

    offsetp[0] = offset;

    return word;
}

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分开我的手 2024-08-27 20:37:57

<代码>& Java 版本中需要 0xff,因为在 Java 中,字节是有符号的。 (有人认为这是一个错误。)

在 C# 中,字节是无符号的,所以 & 0xff 是不必要的。

The & 0xff is required in the Java version because in Java, bytes are signed. (Some argue that this is a bug.)

In C#, bytes are unsigned, so the & 0xff is unnecessary.

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