PHP 对象的 XPath 结果

发布于 2024-08-19 20:15:37 字数 492 浏览 5 评论 0原文

我有一个 xml 文件，它代表许多对象，我在应用程序中有一个类。例如，博客文章：

<blogposts>
  <blogpost id="604">
    <title>afdghadfh</title>
    <body>adfgadfgda</body>
  </blogpost>
  <blogpost id="605">
    <title>dafghadh</title>
    <body>afadf</body>
  </blogpost>
</blogposts>

我想使用 XPath 读取 xml 文件并将结果转换为博客文章对象。是否有任何简单的方法可以将生成的 SimpleXMLElement 对象转换为 blogpost 对象的值？

任何建议表示赞赏。

谢谢。

原文

I have an xml file which represents a number of objects for which I have a class in my application. For example, blogposts:

<blogposts>
  <blogpost id="604">
    <title>afdghadfh</title>
    <body>adfgadfgda</body>
  </blogpost>
  <blogpost id="605">
    <title>dafghadh</title>
    <body>afadf</body>
  </blogpost>
</blogposts>

I would like to read the xml file using XPath and convert the results to blogpost objects. Is there any simple way to convert the resulting SimpleXMLElement Objects into values for a blogpost object?

Any advice appreciated.

Thanks.

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九八野马 2024-08-26 20:15:37

根据需要进行调整。

// blogpost class definition

$blogposts = array();

$xml_resource = new SimpleXMLElement('file.xml', 0, true);

foreach($xml_resource->xpath('/blogposts/blogpost') as $blogpost)
{
    $current_blogpost = new blogpost();
    $current_blogpost->id = (int) $blogpost['id'];
    $current_blogpost->title = (string) $blogpost->title;
    $current_blogpost->body = (string) $blogpost->body;
    $blogposts[] = $current_blogpost;
}

Tweak as needed.

// blogpost class definition

$blogposts = array();

$xml_resource = new SimpleXMLElement('file.xml', 0, true);

foreach($xml_resource->xpath('/blogposts/blogpost') as $blogpost)
{
    $current_blogpost = new blogpost();
    $current_blogpost->id = (int) $blogpost['id'];
    $current_blogpost->title = (string) $blogpost->title;
    $current_blogpost->body = (string) $blogpost->body;
    $blogposts[] = $current_blogpost;
}

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