具有多个参数的 Django 通用视图

发布于 2024-08-19 13:49:32 字数 839 浏览 5 评论 0原文

是否可以在 URL 映射中使用带有附加参数的通用视图 - 即我得到以下模型：

class Route(models.Model):
    area = models.ForeignKey(Area)
    slug = models.SlugField(null=True,blank=True)

    @models.permalink
    def get_absolute_url(self):
        return ('route_details', (), {'area': self.area.slug, 
                                      'slug': self.slug})

这个 URL 映射：

url(r'^(?P<area>[-\w]+)/(?P<slug>[-\w]+)/$','routes.views.route_details',
    name='route_details')

这个简单的视图：

def route_details(self, area, slug):
    route = get_object_or_404(Route, slug=slug)
    return render_to_response("routes/route_details.html", {'route': route})

如您所见，我实际上只是通过路由的 slug 来识别路由区域 slug 只是为了塑造 url（例如routes/central-park/rat-rock）。我可以只使用通用视图做同样的事情吗？

原文

Is it possible to use a generic view with additional parameters in the URL mapping - i.e. I got the following model:

class Route(models.Model):
    area = models.ForeignKey(Area)
    slug = models.SlugField(null=True,blank=True)

    @models.permalink
    def get_absolute_url(self):
        return ('route_details', (), {'area': self.area.slug, 
                                      'slug': self.slug})

This URL-Mapping:

url(r'^(?P<area>[-\w]+)/(?P<slug>[-\w]+)/
And this trivial view:
def route_details(self, area, slug):
    route = get_object_or_404(Route, slug=slug)
    return render_to_response("routes/route_details.html", {'route': route})

As you can see, I'm actually identifying the route just by the route's slug and the area slug is just to shape the url (e.g. routes/central-park/rat-rock). Can I do the same just using a generic view?
,'routes.views.route_details',
    name='route_details')

And this trivial view:

As you can see, I'm actually identifying the route just by the route's slug and the area slug is just to shape the url (e.g. routes/central-park/rat-rock). Can I do the same just using a generic view?

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亢潮 2024-08-26 13:49:32

当然，像这样的东西：

url(r'^(?P<area>[-\w]+)/(?P<slug>[-\w]+)/
应该可以工作。
请务必将 template_object_name 设置为“route”或在模板中使用“object”。
,
    'django.views.generic.list_detail.object_detail',
    {'queryset': Route.objects.all()}
    name='route_details')

应该可以工作。

请务必将 template_object_name 设置为“route”或在模板中使用“object”。

Sure, something like this:

url(r'^(?P<area>[-\w]+)/(?P<slug>[-\w]+)/
Should just work.
Be sure to either set template_object_name to "route" or use "object" in template.
,
    'django.views.generic.list_detail.object_detail',
    {'queryset': Route.objects.all()}
    name='route_details')

Should just work.

Be sure to either set template_object_name to "route" or use "object" in template.

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