有条件地追加到 Makefile 目标内的变量

发布于 2024-08-19 12:50:35 字数 408 浏览 9 评论 0原文

我有一个看起来有点像这样的 GNU Makefile：

LIST = item1

.PHONY: targetMain targetA targetB preA preB

targetMain:
# DO all the work in here
    echo $(LIST)

targetA: preA targetMain
targetB: preB targetMain

preA:
LIST += itemA

preB:
LIST += itemB

这个想法是我运行 make targetA 或 make targetB。他们都做了非常相似的事情，但项目列表不同。问题是变量不是有条件附加的，它总是附加的，这意味着我的输出始终是“item1 itemA itemB”。

如何有条件地附加到变量？

原文

I have a GNU Makefile that looks a bit like this:

LIST = item1

.PHONY: targetMain targetA targetB preA preB

targetMain:
# DO all the work in here
    echo $(LIST)

targetA: preA targetMain
targetB: preB targetMain

preA:
LIST += itemA

preB:
LIST += itemB

The idea is that I either run make targetA or make targetB. Both of them do a very similar thing, but with a different list of items. The problem is that the variable isn't conditionally appended to, it is always appended to, meaning my output is always "item1 itemA itemB".

How can I conditionally append to a variable?

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断爱 2024-08-26 12:50:35

LIST = item1

.PHONY: targetMain targetA targetB

targetMain:
# DO all the work in here
    echo $(LIST)

targetA: LIST+=itemA
targetB: LIST+=itemB

targetA targetB: targetMain

LIST = item1

.PHONY: targetMain targetA targetB

targetMain:
# DO all the work in here
    echo $(LIST)

targetA: LIST+=itemA
targetB: LIST+=itemB

targetA targetB: targetMain

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