如何执行具有多个条件的 while 循环

Question

我在 python 中有一个 while 循环，

condition1=False
condition1=False
val = -1

while condition1==False and condition2==False and val==-1:
    val,something1,something2 = getstuff()

    if something1==10:
        condition1 = True

    if something2==20:
        condition2 = True

'
'

当所有这些条件都成立时，我想跳出循环，上面的代码不起作用，

我原来的

while True:
      if condition1==True and condition2==True and val!=-1:
         break

代码可以正常工作，这是最好的方法吗？

谢谢

Answer 1

将 and 更改为 or。

Answer 2

while not condition1 or not condition2 or val == -1:

但是你原来在一段时间内使用 if 的做法没有任何问题 True 。

Answer 3

您是否注意到在您发布的代码中，condition2 从未设置为False？这样，你的循环体就永远不会被执行。

另请注意，在 Python 中，not condition 优先于 condition == False；同样，condition 优先于 condition == True。

Answer 4

condition1 = False
condition2 = False
val = -1
#here is the function getstuff is not defined, i hope you define it before
#calling it into while loop code

while condition1 and condition2 is False and val == -1:
#as you can see above , we can write that in a simplified syntax.
    val,something1,something2 = getstuff()

    if something1 == 10:
        condition1 = True

    elif something2 == 20:
# here you don't have to use "if" over and over, if have to then write "elif" instead    
    condition2 = True
# ihope it can be helpfull

Answer 5

我不确定它会读起来更好，但你可以执行以下操作：

while any((not condition1, not condition2, val == -1)):
    val,something1,something2 = getstuff()

    if something1==10:
        condition1 = True

    if something2==20:
        condition2 = True

Answer 6

使用像您最初所做的那样的无限循环。它是最干净的，您可以根据需要合并许多条件

while 1:
  if condition1 and condition2:
      break
  ...
  ...
  if condition3: break
  ...
  ...