如何从 makefile 运行 Perl oneliner？
我知道下面的 perl one 衬垫非常简单，可以工作并进行全局替换，A 替换 a；但如何在 makefile 中运行它呢？
perl -pi -e "s/a/A/g" filename
我已经尝试过（我现在认为帖子的其余部分是垃圾，因为 shell 命令执行命令行扩展 - 不是我想要的！）上面的问题仍然存在！
APP = $(shell perl -pi -e "s/a/A/g" filename)
有或没有以下行
EXE = $(APP)
，我总是收到以下错误
make: APP: Command not found
，我认为该错误来自启动 APP 的行
谢谢
I know the perl one liner below is very simple, works and does a global substitution, A for a; but how do I run it in a makefile?
perl -pi -e "s/a/A/g" filename
I have tried (I now think the rest of the post is junk as the shell command does a command line expansion - NOT WHAT I WANT!) The question above still stands!
APP = $(shell perl -pi -e "s/a/A/g" filename)
with and without the following line
EXE = $(APP)
and I always get the following error
make: APP: Command not found
which I assume comes from the line that starts APP
Thanks
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如果你想运行 perl 作为目标操作的一部分，你可以使用
$ cat Makefile all: echo abc | perl -pe 's/a/A/g' $ make echo abc | perl -pe 's/a/A/g' Abc（请注意，
echo之前有一个 TAB 字符。）Perl 的
-i选项用于编辑文件-place，但这会让make感到困惑（除非你正在编写一个 虚假目标）。更典型的模式是从源头制定目标。例如：$ cat Makefile all: bAr bAr: bar.in perl -pe 's/a/A/g' bar.in > bAr $ cat bar.in bar $ make perl -pe 's/a/A/g' bar.in > bAr $ cat bAr bAr如果您让我们知道您想要做什么，我们将能够为您提供更好、更有帮助的答案。
If you want to run perl as part of a target's action, you might use
$ cat Makefile all: echo abc | perl -pe 's/a/A/g' $ make echo abc | perl -pe 's/a/A/g' Abc(Note that there's a TAB character before
echo.)Perl's
-ioption is for editing files in-place, but that will confusemake(unless perhaps you're writing a phony target). A more typical pattern is to make targets from sources. For example:$ cat Makefile all: bAr bAr: bar.in perl -pe 's/a/A/g' bar.in > bAr $ cat bar.in bar $ make perl -pe 's/a/A/g' bar.in > bAr $ cat bAr bArIf you let us know what you're trying to do, we'll be able to give you better, more helpful answers.
您应该显示尽可能小的 Makefile 来演示您的问题，并显示您如何调用它。假设你的 Makefile 看起来像这样，我收到错误消息。请注意，
all:目标中的APP前面有一个制表符。也许您打算这样做：
我没有使用您的 perl 命令，因为它不能按原样为我运行。
您真的想使用 Perl 的替换运算符吗？
perl -pi -e "s/a/A/g"这里是 GNU make 文档。
You should show the smallest possible Makefile which demonstrates your problem, and show how you are calling it. Assuming your Makefile looks something like this, I get the error message. Note that there is a tab character preceding the
APPin theall:target.Perhaps you meant to do this instead:
I did not use your
perlcommand because it does not run for me as-is.Do you really mean to use Perl's substitution operator?
perl -pi -e "s/a/A/g"Here is a link to GNU make documentation.