应用程序未进入快速枚举循环

发布于 2024-08-18 12:25:20 字数 739 浏览 7 评论 0原文

经过多次调试，我确定这段代码忽略了快速枚举循环并盲目地跳到末尾：

-(void)loadOutAnnotations
{
    NSLog(@"entering Annotation enumeration Loop");

    iProspectFresno_LiteAppDelegate *appDelegate =(iProspectFresno_LiteAppDelegate *)[[UIApplication sharedApplication] delegate];

    FlipsideViewController *viewController = (FlipsideViewController *)[[UIApplication sharedApplication] delegate];

    CLLocationCoordinate2D workingCoordinate;
    NSLog(@"initializing");
    NSMutableArray* mines = [[NSMutableArray alloc] initWithArray(NSMutableArray *)appDelegate.mines];
    for (id mine in mines)
    {
        NSLog(@"in the loop");
        //rest of loop code
   }
}

控制台打印“进入注释枚举循环”以及“初始化”，但它似乎完全绕过了枚举循环，因为它不是“在循环中”打印。我做错了什么？

原文

after much debugging, I have determined that this code is ignoring the fast enumeration loop and blindly jumping to the end:

-(void)loadOutAnnotations
{
    NSLog(@"entering Annotation enumeration Loop");

    iProspectFresno_LiteAppDelegate *appDelegate =(iProspectFresno_LiteAppDelegate *)[[UIApplication sharedApplication] delegate];

    FlipsideViewController *viewController = (FlipsideViewController *)[[UIApplication sharedApplication] delegate];

    CLLocationCoordinate2D workingCoordinate;
    NSLog(@"initializing");
    NSMutableArray* mines = [[NSMutableArray alloc] initWithArray(NSMutableArray *)appDelegate.mines];
    for (id mine in mines)
    {
        NSLog(@"in the loop");
        //rest of loop code
   }
}

the console prints "entering Annotation enumeration Loop" as well as the "initializing," but it seems to bypass the enumeration loop completely, as it is not printing "in the loop." what am I doing wrong?

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