在 Django 的管理界面中发布表单
我正在编写一个 Django 管理操作来批量发送电子邮件联系人。该操作定义如下：
def email_selected(self,request,queryset):
rep_list = []
for each in queryset:
reps = CorporatePerson.objects.filter(company_id = Company.objects.get(name=each.name))
contact_reps = reps.filter(is_contact=True)
for rep in contact_reps:
rep_list.append(rep)
return email_form(request,queryset,rep_list)
email_form 作为视图存在，并使用以下代码填充模板：
def email_form(request,queryset,rep_list):
if request.method == 'POST':
form = EmailForm(request.POST)
if form.is_valid():
cd = form.cleaned_data
send_mail(
cd['subject'],
cd['message'],
cd.get('email','noreply@localboast'),['[email protected]'],
)
return HttpResponseRedirect('thanks')
else:
form = EmailForm()
return render_to_response('corpware/admin/email-form.html',{'form':form,})
模板存在如下：
<body>
<form action="/process_mail/" method="post">
<table>
{{ form.as_table }}
</table>
<input type = "submit" value = "Submit">
</form>
</body>
/process_mail/ 硬链接到 urls.py 中的另一个视图 - 这是一个问题。我真的很喜欢它，这样我就不必使用
有没有一种方法可以使表单 POST到其自身（
I'm writing a Django admin action to mass e-mail contacts. The action is defined as follows:
def email_selected(self,request,queryset):
rep_list = []
for each in queryset:
reps = CorporatePerson.objects.filter(company_id = Company.objects.get(name=each.name))
contact_reps = reps.filter(is_contact=True)
for rep in contact_reps:
rep_list.append(rep)
return email_form(request,queryset,rep_list)
email_form exists as a view and fills a template with this code:
def email_form(request,queryset,rep_list):
if request.method == 'POST':
form = EmailForm(request.POST)
if form.is_valid():
cd = form.cleaned_data
send_mail(
cd['subject'],
cd['message'],
cd.get('email','noreply@localboast'),['[email protected]'],
)
return HttpResponseRedirect('thanks')
else:
form = EmailForm()
return render_to_response('corpware/admin/email-form.html',{'form':form,})
and the template exists as follows:
<body>
<form action="/process_mail/" method="post">
<table>
{{ form.as_table }}
</table>
<input type = "submit" value = "Submit">
</form>
</body>
/process_mail/ is hardlinked to another view in urls.py - which is a problem. I'd really like it so that I don't have to use <form action="/process_mail/" method="post"> but unfortunately I can't seem to POST the user inputs to the view handler without the admin interface for the model being reloaded in it's place (When I hit the submit button with , the administration interface appears, which I don't want.)
Is there a way that I could make the form POST to itself (<form action="" method="post">) so that I can handle inputs received in email_form? Trying to handle inputs with extraneous URLs and unneeded functions bothers me, as I'm hardcoding URLs to work with the code.
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您可以使用 django 的内置 url 标签来避免硬编码链接。参见...
http://docs.djangoproject.com/en /dev/ref/templates/builtins/#url
您可能最好设置一个由 cron 作业触发的群发邮件程序，而不是在帖子上触发。
查看我在这里发布的答案
Django 计划作业
另外，如果你坚持在视图更新时触发 email_send 函数，也许看看在
http://docs.djangoproject.com/en/dev/topics/signals/
You can use django's inbuilt url tag to avoid hardcoding links. see...
http://docs.djangoproject.com/en/dev/ref/templates/builtins/#url
Chances are you'd be better off setting up a mass mailer to be triggered off by a cron job rather than on the post.
Check out the answer I posted here
Django scheduled jobs
Also if you insist on triggering the email_send function on a view update perhaps look at
http://docs.djangoproject.com/en/dev/topics/signals/