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Question

我正在尝试将数据从 vb.net 应用程序发布到位于服务器上的 Web 服务 asmx！

为了从 vb.net 应用程序发布数据，我使用以下代码：

Public Function Post(ByVal url As String, ByVal data As String) As String
    Dim vystup As String = Nothing
    Try
        'Our postvars
        Dim buffer As Byte() = Encoding.ASCII.GetBytes(data)
        'Initialisation, we use localhost, change if appliable
        Dim WebReq As HttpWebRequest = DirectCast(WebRequest.Create(url), HttpWebRequest)
        'Our method is post, otherwise the buffer (postvars) would be useless
        WebReq.Method = "POST"
        'We use form contentType, for the postvars.
        WebReq.ContentType = "application/x-www-form-urlencoded"
        'The length of the buffer (postvars) is used as contentlength.
        WebReq.ContentLength = buffer.Length
        'We open a stream for writing the postvars
        Dim PostData As Stream = WebReq.GetRequestStream()
        'Now we write, and afterwards, we close. Closing is always important!
        PostData.Write(buffer, 0, buffer.Length)
        PostData.Close()
        'Get the response handle, we have no true response yet!
        Dim WebResp As HttpWebResponse = DirectCast(WebReq.GetResponse(), HttpWebResponse)
        'Let's show some information about the response
        Console.WriteLine(WebResp.StatusCode)
        Console.WriteLine(WebResp.Server)

        'Now, we read the response (the string), and output it.
        Dim Answer As Stream = WebResp.GetResponseStream()
        Dim _Answer As New StreamReader(Answer)

        'Congratulations, you just requested your first POST page, you
        'can now start logging into most login forms, with your application
        'Or other examples.
        vystup = _Answer.ReadToEnd()
    Catch ex As Exception
        MessageBox.Show(ex.Message)
    End Try

    Return vystup.Trim() & vbLf
End Function 

现在我如何在 asmx 服务中检索此数据？

Answer 1

所有这些代码使得您看起来像是将数据发布到常规网页（可能是 .Net Web 表单），而不是 Web 服务。如果它是一个 Web 服务，您将改为传递 XML。因此，假设它是一个 .Net Web 表单，您可以使用 Request.Form("whatever-your-variable-is-known") 访问原始 POST 数据。但是，您似乎没有在 POST 数据中传递变量 = xyz，因此您需要在 Web 表单中访问原始 Request.InputStream

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
    Dim T As String
    Using SR As New System.IO.StreamReader(Request.InputStream)
        T = SR.ReadToEnd()
    End Using
End Sub