如果我已经连接到服务器。然后我如何显示异常说它已经连接

发布于 2024-08-17 13:36:44 字数 3069 浏览 1 评论 0原文

如果用户单击连接而不输入任何输入,如何添加显示必须输入输入的异常?我希望如果用户单击连接按钮而不输入名称、IP 和端口,则会显示一个消息框。 [已解决]

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Net.Sockets;
using System.Threading;

namespace SocketClient
{

    public partial class SocketClient : Form
    {
        System.Net.Sockets.TcpClient clientSocket = new System.Net.Sockets.TcpClient();
        NetworkStream serverStream = default(NetworkStream);
        string readData = null;


        public SocketClient()
        {
            InitializeComponent();
        }


        private void getMessage()
        {
            while (true)
            {
                serverStream = clientSocket.GetStream();
                int buffSize = 0;
                byte[] inStream = new byte[10025];
                buffSize = clientSocket.ReceiveBufferSize;
                serverStream.Read(inStream, 0, buffSize);
                string returndata = System.Text.Encoding.ASCII.GetString(inStream);
                readData = "" + returndata;
                msg();
            }
        }


        private void msg()
        {
            if (this.InvokeRequired)
                this.Invoke(new MethodInvoker(msg));
            else
                textDisplay.Text = textDisplay.Text + Environment.NewLine + " >> " + readData;
        }


        private void buttonConnect_Click(object sender, EventArgs e)
        {

            readData = "Conected to NYP Server ...";
            msg();
            //clientSocket.Connect("127.0.0.1", 8888);
            clientSocket.Connect(textIP.Text, Convert.ToInt32(textPort.Text));
            serverStream = clientSocket.GetStream();

            byte[] outStream = System.Text.Encoding.ASCII.GetBytes(textName.Text + "$");
            serverStream.Write(outStream, 0, outStream.Length);
            serverStream.Flush();

            Thread ctThread = new Thread(getMessage);
            ctThread.Start();
        }

        private void buttonSend_Click(object sender, EventArgs e)
        {
            // Show msg box if no server is connected
            if (serverStream == null)
            {
                MessageBox.Show("Please connect to a server first!");
                return;
            }

            // Send text
            byte[] outStream = System.Text.Encoding.ASCII.GetBytes(textSend.Text + "$");
            serverStream.Write(outStream, 0, outStream.Length);
            serverStream.Flush();

            // Clear text
            textSend.Text = "";

        }

        private void textDisplay_TextChanged(object sender, EventArgs e)
        {
            textDisplay.SelectionStart = textDisplay.Text.Length;
            textDisplay.ScrollToCaret();
            textDisplay.Refresh();
        }

        private void textSend_TextChanged(object sender, EventArgs e)
        {
            buttonSend.Enabled = !string.IsNullOrEmpty(textSend.Text);
        }
    }
}

how to add in exception showing the input has to be enter, if the user click on connect without entering any input? i would like the have a message box show if the user click on the connect button without entering the name, ip and port. [SOLVED]

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Net.Sockets;
using System.Threading;

namespace SocketClient
{

    public partial class SocketClient : Form
    {
        System.Net.Sockets.TcpClient clientSocket = new System.Net.Sockets.TcpClient();
        NetworkStream serverStream = default(NetworkStream);
        string readData = null;


        public SocketClient()
        {
            InitializeComponent();
        }


        private void getMessage()
        {
            while (true)
            {
                serverStream = clientSocket.GetStream();
                int buffSize = 0;
                byte[] inStream = new byte[10025];
                buffSize = clientSocket.ReceiveBufferSize;
                serverStream.Read(inStream, 0, buffSize);
                string returndata = System.Text.Encoding.ASCII.GetString(inStream);
                readData = "" + returndata;
                msg();
            }
        }


        private void msg()
        {
            if (this.InvokeRequired)
                this.Invoke(new MethodInvoker(msg));
            else
                textDisplay.Text = textDisplay.Text + Environment.NewLine + " >> " + readData;
        }


        private void buttonConnect_Click(object sender, EventArgs e)
        {

            readData = "Conected to NYP Server ...";
            msg();
            //clientSocket.Connect("127.0.0.1", 8888);
            clientSocket.Connect(textIP.Text, Convert.ToInt32(textPort.Text));
            serverStream = clientSocket.GetStream();

            byte[] outStream = System.Text.Encoding.ASCII.GetBytes(textName.Text + "$");
            serverStream.Write(outStream, 0, outStream.Length);
            serverStream.Flush();

            Thread ctThread = new Thread(getMessage);
            ctThread.Start();
        }

        private void buttonSend_Click(object sender, EventArgs e)
        {
            // Show msg box if no server is connected
            if (serverStream == null)
            {
                MessageBox.Show("Please connect to a server first!");
                return;
            }

            // Send text
            byte[] outStream = System.Text.Encoding.ASCII.GetBytes(textSend.Text + "$");
            serverStream.Write(outStream, 0, outStream.Length);
            serverStream.Flush();

            // Clear text
            textSend.Text = "";

        }

        private void textDisplay_TextChanged(object sender, EventArgs e)
        {
            textDisplay.SelectionStart = textDisplay.Text.Length;
            textDisplay.ScrollToCaret();
            textDisplay.Refresh();
        }

        private void textSend_TextChanged(object sender, EventArgs e)
        {
            buttonSend.Enabled = !string.IsNullOrEmpty(textSend.Text);
        }
    }
}

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评论(3

何必那么矫情 2024-08-24 13:36:44
if(string.IsNullOrEmpty(textIP.Text) || string.IsNullOrEmpty(textPort.Text)  || string.IsNullOrEmpty(textName.Text))
{
   MessageBox.Show("Please enter IP address, Port #, and Name");
}
else
{
  //they entered stuff...so, try to connect..
}

if(string.IsNullOrEmpty(textIP.Text) || string.IsNullOrEmpty(textPort.Text)  || string.IsNullOrEmpty(textName.Text))
{
   MessageBox.Show("Please enter IP address, Port #, and Name");
}
else
{
  //they entered stuff...so, try to connect..
}

末蓝 2024-08-24 13:36:44

您可以使用TcpClient.Connected属性来检查连接是否已建立。

if(clientSocket.Connected){
  .... show error message here
}
else{
  ... go ahead  
} 

You can use TcpClient.Connected property to check whether a connection is already established or not.

if(clientSocket.Connected){
  .... show error message here
}
else{
  ... go ahead  
} 
傾旎 2024-08-24 13:36:44

您的表单包含对 TcpClientNetworkStream 实例的引用。它们都实现了IDisposable,因此必须显式地处理它们。您必须重写表单的 Dispose 方法,并在这些实例不为 null 时释放它们。

Your form holds references to both a TcpClient and a NetworkStream instance. Both of these implement IDisposable, so that they must be disposed of explicitly. You must override the Dispose method of the form and dispose of these instances if they are not null.

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