如何在MySQL过程中创建唯一的临时表？

发布于 2024-08-17 04:04:37 字数 308 浏览 5 评论 0原文

我在程序中创建临时表，但总是收到错误“表已存在”。

然后我尝试创建一个随机名称以避免冲突，但我对如何执行 SQL 字符串了解不够

SET @tbName = CONCAT('temp', random_id);

PREPARE stmt1 FROM 'CREATE TEMPORARY TABLE ? (`FIELDNAME` float NOT NULL);';
EXECUTE stmt1 using @tbName;
DEALLOCATE PREPARE stmt1;

上面的代码不起作用。为什么？如何纠正呢？

原文

I was creating a temporary table in my procedure, but I always got an error "table already exists".

Then I tried to create a random name to avoid collision but I don't know enough about how to execute SQL strings

SET @tbName = CONCAT('temp', random_id);

PREPARE stmt1 FROM 'CREATE TEMPORARY TABLE ? (`FIELDNAME` float NOT NULL);';
EXECUTE stmt1 using @tbName;
DEALLOCATE PREPARE stmt1;

The code above doesn't works. Why? How to correct it?

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难理解 2024-08-24 04:04:37

 mysql> set @table_name := 'mytable';
 Query OK, 0 rows affected (0.02 sec)

 mysql> set @sql_text:=concat('create table ',@table_name,'(id int unsigned)');
 Query OK, 0 rows affected (0.00 sec)

来自 http://rpbouman.blogspot.com /2005/11/mysql-5-prepared-statement-syntax-and.html

 mysql> set @table_name := 'mytable';
 Query OK, 0 rows affected (0.02 sec)

 mysql> set @sql_text:=concat('create table ',@table_name,'(id int unsigned)');
 Query OK, 0 rows affected (0.00 sec)

from http://rpbouman.blogspot.com/2005/11/mysql-5-prepared-statement-syntax-and.html

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