将 0A 替换为 \n

发布于 2024-08-16 23:09:00 字数 960 浏览 2 评论 0原文

我当时正在开始开发一个简单的十六进制编辑器（当时只能读取）。我想用 OA 替换 "\n"，我正在尝试使用以下代码：

#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;

int main() {
   ifstream infile;
   int crtchar = (int)infile.get();
   infile.open("test.txt", ifstream::in);
   while(infile.good())
   {
      if(crtchar != 0xA)
         cout << hex << setfill('0') << setw(2) << crtchar << ":";
      else
         cout << endl;
   }
   cout << "\n=====================================\n";
   infile.close();
   return 0;
}

它编译时没有错误，但是当我尝试执行它时，我什么也没得到:

C:\Documents and Settings\Nathan Campos\Desktop>hex
========================================
C:\Documents and Settings\Nathan Campos\Desktop>

这是在我添加用 OA 替换 \n 的功能之后发生的，因为之前它工作得很好。 出了什么问题？

原文

I'm at the time beginning the development of a simple hex editor(that only reads at the time). I want to substitute OA for "\n", I'm trying with this code:

#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;

int main() {
   ifstream infile;
   int crtchar = (int)infile.get();
   infile.open("test.txt", ifstream::in);
   while(infile.good())
   {
      if(crtchar != 0xA)
         cout << hex << setfill('0') << setw(2) << crtchar << ":";
      else
         cout << endl;
   }
   cout << "\n=====================================\n";
   infile.close();
   return 0;
}

It compiles without errors, but when I try to execute it, I just got nothing: