将 NSPredicate 与 Core Data 结合使用以建立深层关系

发布于 2024-08-16 22:35:02 字数 600 浏览 3 评论 0原文

我有一个 NSArrayController,companiesController 绑定到顶级核心数据实体 Companies

一个公司有很多部门,一个部门有很多员工;这些由一对多关系、部门员工 表示。

基于 Employee 的属性 salary 我认为我可以动态地执行此操作,以便根据 UI 调用的方法内的薪水进行过滤:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY departments.employees.salary < %@", [NSNumber numberWithInt:23000]];
[companiesController setFilterPredicate:predicate];

唉,这给了我错误:<代码> - [NSCFSet比较:]:无法识别的选择器发送到实例。

I have an NSArrayController, companiesController bound to a top level Core Data entity, Companies.

A Company has many Department's, and a Department has many Employee; these are represented by the 1-to-many relationships, departments and employees.

Based on the attribute salary of an Employee I thought I could dynamically do this for filtering based on salary inside a UI-called method:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY departments.employees.salary < %@", [NSNumber numberWithInt:23000]];
[companiesController setFilterPredicate:predicate];

Alas, this gives me the error: -[NSCFSet compare:]: unrecognized selector sent to instance.

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一笔一画续写前缘 2024-08-23 22:35:02

在这种情况下不允许使用多个对多键。

相反,您可以执行以下操作:

  1. 通过向 Department 实体添加“过滤器”标志(布尔值)属性来修改数据模型。
  2. 创建一个方法来:获取所有 Department 对象,将符合谓词后半部分条件的部门的筛选标志设置为 YES,将其他部门的筛选标志设置为 NO,然后保存。
  3. 在 Company 谓词中使用过滤标志。

代码更改(步骤 3):

    //NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY departments.employees.salary < %@", [NSNumber numberWithInt:23000]];
    [self setDeptFilter:23000];
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY depts.filter == YES"];
    [companiesController setFilterPredicate:predicate];

以及新方法(步骤 2):

- (void)setDeptFilter:(NSUInteger)salary {
    NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];

    NSEntityDescription *entity = [NSEntityDescription entityForName:@"Department" inManagedObjectContext:self.managedObjectContext];
    [fetchRequest setEntity:entity];

    NSError *error = nil;

    // fetch all Department objects
    NSArray *array = [self.managedObjectContext executeFetchRequest:fetchRequest error:&error];

    [fetchRequest release];

    if (error) {
        NSLog(@"Error fetching Departments %@, %@", error, [error userInfo]);
        abort();
    }

    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY emps.salary < %@",[NSNumber numberWithInteger:salary]];
    NSArray *filterArray = [array filteredArrayUsingPredicate:predicate];

    // set filter flag to YES for the departments that meet the criteria
    for (Department *dep in filterArray) {
        dep.filter = [NSNumber numberWithBool:YES];
    }

    NSMutableArray *diffArray = [array mutableCopy];
    [diffArray removeObjectsInArray:filterArray];

    // set filter flag to NO for the departments that do NOT meet the criteria
    for (Department *dep in diffArray) {
        dep.filter = [NSNumber numberWithBool:NO];
    }

    [diffArray release];

    // save
    if ([self.managedObjectContext hasChanges] && ![self.managedObjectContext save:&error]) {
        NSLog(@"Unresolved error %@, %@", error, [error userInfo]);
        abort();
    } 
}

Multiple to-many keys are not allowed in this case.

Instead, you could do the following:

  1. Modify the data model by adding a "filter" flag (Boolean) attribute to the Department entity.
  2. Create a method to: fetch all the Department objects, set the filter flag to YES for the departments that meet the criteria of the second half of your predicate, set the filter flag to NO for the other departments, and save.
  3. Use the filter flag in the Company predicate.

Code changes (step 3):

    //NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY departments.employees.salary < %@", [NSNumber numberWithInt:23000]];
    [self setDeptFilter:23000];
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY depts.filter == YES"];
    [companiesController setFilterPredicate:predicate];

And the new method (step 2):

- (void)setDeptFilter:(NSUInteger)salary {
    NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];

    NSEntityDescription *entity = [NSEntityDescription entityForName:@"Department" inManagedObjectContext:self.managedObjectContext];
    [fetchRequest setEntity:entity];

    NSError *error = nil;

    // fetch all Department objects
    NSArray *array = [self.managedObjectContext executeFetchRequest:fetchRequest error:&error];

    [fetchRequest release];

    if (error) {
        NSLog(@"Error fetching Departments %@, %@", error, [error userInfo]);
        abort();
    }

    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY emps.salary < %@",[NSNumber numberWithInteger:salary]];
    NSArray *filterArray = [array filteredArrayUsingPredicate:predicate];

    // set filter flag to YES for the departments that meet the criteria
    for (Department *dep in filterArray) {
        dep.filter = [NSNumber numberWithBool:YES];
    }

    NSMutableArray *diffArray = [array mutableCopy];
    [diffArray removeObjectsInArray:filterArray];

    // set filter flag to NO for the departments that do NOT meet the criteria
    for (Department *dep in diffArray) {
        dep.filter = [NSNumber numberWithBool:NO];
    }

    [diffArray release];

    // save
    if ([self.managedObjectContext hasChanges] && ![self.managedObjectContext save:&error]) {
        NSLog(@"Unresolved error %@, %@", error, [error userInfo]);
        abort();
    } 
}
↙温凉少女 2024-08-23 22:35:02

您也可以使用子查询来完成此操作。

获取所有部门。 “of”关系与公司与多个部门的关系相反:

-(void)printDepartmentsWithSalaryHigherThan:(int)salary inContext:(NSManagedObjectContext *)context {    
    NSFetchRequest *request = [[NSFetchRequest alloc ]init];
    request.entity = [NSEntityDescription entityForName:@"Department" inManagedObjectContext:context];
    request.predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(employees, $emp, $emp.salary > %@ ).@count > 0", [NSNumber numberWithInt:salary]];

    for(Department *dep in [context executeFetchRequest:request error:nil]){
        NSLog(@"Department: %@", dep.depName);
        NSLog(@"in Company: %@", dep.of.compName);
    }
    [request release];
}

或者,如果您有更多公司,并且只希望那些公司的员工工资“高于”某个金额。基于子查询结果的子查询

-(void)printCompaniesWithHigherSalaryThan:(int)salary inContext:(NSManagedObjectContext *)context {
    NSFetchRequest *request = [[NSFetchRequest alloc ]init];
    request.entity = [NSEntityDescription entityForName:@"Company" inManagedObjectContext:context];
    request.predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(departments, $dep, SUBQUERY($dep.employees,$emp,$emp.salary > %@).@count > 0 ).@count > 0", [NSNumber numberWithInt:salary]];

    for(Company *c in [context executeFetchRequest:request error:nil]){
        NSLog(@"Company: %@", c.compName);
    }
    [request release];
}

You could also do this using subqueries.

Get all departments. The 'of' relationship is the inverse of company to-many departments:

-(void)printDepartmentsWithSalaryHigherThan:(int)salary inContext:(NSManagedObjectContext *)context {    
    NSFetchRequest *request = [[NSFetchRequest alloc ]init];
    request.entity = [NSEntityDescription entityForName:@"Department" inManagedObjectContext:context];
    request.predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(employees, $emp, $emp.salary > %@ ).@count > 0", [NSNumber numberWithInt:salary]];

    for(Department *dep in [context executeFetchRequest:request error:nil]){
        NSLog(@"Department: %@", dep.depName);
        NSLog(@"in Company: %@", dep.of.compName);
    }
    [request release];
}

Or, if you have more companies and just want the companies that have an employee with a salary 'higher than' some amount. A subquery based on the result of a subquery

-(void)printCompaniesWithHigherSalaryThan:(int)salary inContext:(NSManagedObjectContext *)context {
    NSFetchRequest *request = [[NSFetchRequest alloc ]init];
    request.entity = [NSEntityDescription entityForName:@"Company" inManagedObjectContext:context];
    request.predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(departments, $dep, SUBQUERY($dep.employees,$emp,$emp.salary > %@).@count > 0 ).@count > 0", [NSNumber numberWithInt:salary]];

    for(Company *c in [context executeFetchRequest:request error:nil]){
        NSLog(@"Company: %@", c.compName);
    }
    [request release];
}
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